Azzera filtri
Azzera filtri

how to develope loop to save the 'n' elements from the vectors

2 visualizzazioni (ultimi 30 giorni)
clc;
clear;
A= [14,51,2,15,........,7 ] % this is known
p1=A[1]
p2=A[2]
.
.
.
.
.
pn=A[n]
%%% i need to use p1,p2,p3,...pn in another equation. so i dont know to to save this elements from A. how to use loop to that it automatically get saved for n elements

Risposte (2)

Matt J
Matt J il 15 Set 2021
It is not a good idea to store A(i) in separate variables. You should probably just write your equation in terms of vector operations on A, which you already have.
  2 Commenti
gourav pandey
gourav pandey il 15 Set 2021
Hii Matt, thank you
i fully agree with you. actually, i am a beginner, so no idea how to use.
if my function is in this way
fun= p1*r^2+p2*ln(r)+p3*cos(theta)/r+p4*sin(theta)/r+(pn*r^(-n+2))*cos(n*theta)
then how to do that?
Matt J
Matt J il 15 Set 2021
A(1)*r^2+A(2)*ln(r)+A(3)*cos(theta)/r+A(4)*sin(theta)/r+(A(n)*r^(-n+2))*cos(n*theta)

Accedi per commentare.


Awais Saeed
Awais Saeed il 15 Set 2021
Although it is not prefered to name variables in a loop but if you striclty want to do this in loops than you can use eval(). Note that using this method is NOT RECOMMENDED. It has been said many times in this forum and by MATLAB itself.
clc;
clear;
A= [14,51,2,15,7]
A = 1×5
14 51 2 15 7
for col = 1:1:size(A,2)
eval(['p',num2str(col),'=A(',num2str(col),')'])
end
p1 = 14
p2 = 51
p3 = 2
p4 = 15
p5 = 7
  1 Commento
Stephen23
Stephen23 il 15 Set 2021
Modificato: Stephen23 il 15 Set 2021
Note that this is slower and more complex than simply using the vector directly.

Accedi per commentare.

Categorie

Scopri di più su Loops and Conditional Statements in Help Center e File Exchange

Prodotti


Release

R2020b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by