Fitting gaussian curve on my data with same under curve area and start and end points

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I have a curve, as presented below. And want to fit a Gaussian curve on it, which has the same under curve area, start point, and end point. I would be appreciated if somebody let me know how I should do that?
The X and Y data are attached.

Risposta accettata

Mathieu NOE
Mathieu NOE il 21 Set 2021
hello
check this code (below)
plot
code
clc
clearvars
load Data_X.mat
load Data_Y.mat
x = Data_X;
y = Data_Y;
clear Data_X Data_Y
%% aera under data curve
y_area = trapz(x,y); % trapz integrates y with respect to the coordinates or scalar spacing specified by x.
%% define start / stop time points
threshold = 1e-3; % your value here
[t0_pos,s0_pos,t0_neg,s0_neg]= crossing_V7(y,x,threshold,'linear'); % positive (pos) and negative (neg) slope crossing points
% ind => time index (samples)
% t0 => corresponding time (x) values
% s0 => corresponding function (y) values , obviously they must be equal to "threshold"
%% gaussian pulse fit
% time center = mean of t0_pos and t0_neg
offset = 0.5*(t0_pos + t0_neg);
f0 = 6/(t0_neg - t0_pos); % frequency of the pulse to get 6 sigma into the time span between t0_pos and t0_neg (you can change from 6 to 3 to get a wider peak)
Var_Sq = 1; % pulse variance (squared) - default value - we will corect the amplitude below
signal_pulse = exp(-(((x-offset).^2).*(f0^2))./Var_Sq);
signal_pulse_area = trapz(x,signal_pulse); % aera under curve // trapz integrates y with respect to the coordinates or scalar spacing specified by x.
signal_pulse_amplitude_correction = y_area/signal_pulse_area;
signal_pulse = signal_pulse*signal_pulse_amplitude_correction;
signal_pulse_area = trapz(x,signal_pulse); % now we can see we have same area under curve as input data
figure(1)
plot(x,y,'b',x,signal_pulse,'r',t0_pos,s0_pos,'+k',t0_neg,s0_neg,'+g','linewidth',2,'markersize',12);grid on
legend('data','pulse signal','start point','stop point');
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
function [t0_pos,s0_pos,t0_neg,s0_neg] = crossing_V7(S,t,level,imeth)
% [ind,t0,s0,t0close,s0close] = crossing_V6(S,t,level,imeth,slope_sign) % older format
% CROSSING find the crossings of a given level of a signal
% ind = CROSSING(S) returns an index vector ind, the signal
% S crosses zero at ind or at between ind and ind+1
% [ind,t0] = CROSSING(S,t) additionally returns a time
% vector t0 of the zero crossings of the signal S. The crossing
% times are linearly interpolated between the given times t
% [ind,t0] = CROSSING(S,t,level) returns the crossings of the
% given level instead of the zero crossings
% ind = CROSSING(S,[],level) as above but without time interpolation
% [ind,t0] = CROSSING(S,t,level,par) allows additional parameters
% par = {'none'|'linear'}.
% With interpolation turned off (par = 'none') this function always
% returns the value left of the zero (the data point thats nearest
% to the zero AND smaller than the zero crossing).
%
% check the number of input arguments
error(nargchk(1,4,nargin));
% check the time vector input for consistency
if nargin < 2 | isempty(t)
% if no time vector is given, use the index vector as time
t = 1:length(S);
elseif length(t) ~= length(S)
% if S and t are not of the same length, throw an error
error('t and S must be of identical length!');
end
% check the level input
if nargin < 3
% set standard value 0, if level is not given
level = 0;
end
% check interpolation method input
if nargin < 4
imeth = 'linear';
end
% make row vectors
t = t(:)';
S = S(:)';
% always search for zeros. So if we want the crossing of
% any other threshold value "level", we subtract it from
% the values and search for zeros.
S = S - level;
% first look for exact zeros
ind0 = find( S == 0 );
% then look for zero crossings between data points
S1 = S(1:end-1) .* S(2:end);
ind1 = find( S1 < 0 );
% bring exact zeros and "in-between" zeros together
ind = sort([ind0 ind1]);
% and pick the associated time values
t0 = t(ind);
s0 = S(ind);
if ~isempty(ind)
if strcmp(imeth,'linear')
% linear interpolation of crossing
for ii=1:length(t0)
%if abs(S(ind(ii))) > eps(S(ind(ii))) % MATLAB V7 et +
if abs(S(ind(ii))) > eps*abs(S(ind(ii))) % MATLAB V6 et - EPS * ABS(X)
% interpolate only when data point is not already zero
NUM = (t(ind(ii)+1) - t(ind(ii)));
DEN = (S(ind(ii)+1) - S(ind(ii)));
slope = NUM / DEN;
slope_sign(ii) = sign(slope);
t0(ii) = t0(ii) - S(ind(ii)) * slope;
s0(ii) = level;
end
end
end
% extract the positive slope crossing points
ind_pos = find(sign(slope_sign)>0);
t0_pos = t0(ind_pos);
s0_pos = s0(ind_pos);
% extract the negative slope crossing points
ind_neg = find(sign(slope_sign)<0);
t0_neg = t0(ind_neg);
s0_neg = s0(ind_neg);
else
% empty output
ind_pos = [];
t0_pos = [];
s0_pos = [];
% extract the negative slope crossing points
ind_neg = [];
t0_neg = [];
s0_neg = [];
end
end

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