fft is not showing correct frequency or amplitude
38 visualizzazioni (ultimi 30 giorni)
Mostra commenti meno recenti
I generated a sample signal using sum of three sine waves. When I plot the signal using fft command to view the individual frequency components, I always get an error in the second (i.e., second in ascending order) frequency component. It either shows up as half the correct frequency or some multiple (twice/ four times, etc). If the frequency is correct, the amplitude is incorrect. The other two frequencies and amplitudes are always correct.
I tried adding a fourth signal, but the same problem repeats with the second signal only. All others are correct. I tried with two signals only and the result is the same. Second signal is wrong.
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/756049/image.jpeg)
Tried restarting Matlab, but it repeats. I tried different values of frequencies and amplitudes, but it is always the second in ascending order which misbehaves. Did not try more than 4 frequencies. I am totally flabbergasted! I am not very familiar with fft, Am trying to learn. Attaching the code and output figure. Any help would be welcome please.
clear all;
close all;
f1=1; f2=2; f3=3; f4=4; % freq of 4 signals, Hz
A1=1; A2=0; A3=0; A4=0;% Amplitudes of 4 signals
f_max=max([f1 f2 f3 f4]); % max of all signal frequencies
dt=1/(f_max*10); % time step
t=0:dt:2000*dt; % time vector 1
x = A1*cos(2*pi*f1*t)+1*cos(A2*pi*f2*t)+A3*cos(2*pi*f3*t)+A4*cos(2*pi*f4*t); % final signal
fs=1/dt; % sampling rate
tm=0:1/fs:(length(x)-1)/fs; % time vector 2
X=fft(x,length(x))*(2/length(x)); %fft of final signal
mag_X = abs(X); % magnitude
freq=0:1/tm(end):fs/2-(1/tm(end)); % compute frequency
plot(freq,mag_X(1:length(freq))); % fft plot
xlabel('Freq')
ylabel('Amplitude')
0 Commenti
Risposta accettata
VBBV
il 2 Ott 2021
clear all;
close all;
f1=1; f2=2; f3=3; f4=4; % freq of 4 signals, Hz
A1=1; A2=0; A3=0; A4=0;% Amplitudes of 4 signals
f_max=max([f1 f2 f3 f4]); % max of all signal frequencies
dt=1/(f_max*10); % time step
t=0:dt:2000*dt; % time vector 1
x = A1*cos(2*pi*f1*t)+A2*cos(2*pi*f2*t)+A3*cos(2*pi*f3*t)+A4*cos(2*pi*f4*t); % final signal
fs=1/dt; % sampling rate
tm=0:1/fs:(length(x)-1)/fs; % time vector 2
X=fft(x,length(x))*(2/length(x)); %fft of final signal
mag_X = abs(X); % magnitude
freq=0:1/tm(end):fs/2-(1/tm(end)); % compute frequency
plot(freq,mag_X(1:length(freq))); % fft plot
xlabel('Freq')
ylabel('Amplitude')
Can you check the difference now ? whether you get same error?
I think you have a typo for the amplitude in second term of
x = A1*cos(2*pi*f1*t)+A2*cos(2*pi*f2*t)+A3*cos(2*pi*f3*t)+A4*cos(2*pi*f4*t); % final signal
It should be A2*cos(2*pi*f2*t) and not 1*(cos(A2*pi*f2*t))
2 Commenti
VBBV
il 2 Ott 2021
clear all;
close all;
f1=1; f2=2; f3=3; f4=4; % freq of 4 signals, Hz
A1=1; A2=2; A3=3; A4=4;% Amplitudes of 4 signals
f_max=max([f1 f2 f3 f4]); % max of all signal frequencies
dt=1/(f_max*10); % time step
t=0:dt:2000*dt; % time vector 1
x = A1*cos(2*pi*f1*t)+A2*cos(2*pi*f2*t)+A3*cos(2*pi*f3*t)+A4*cos(2*pi*f4*t); % final signal
fs=1/dt; % sampling rate
tm=0:1/fs:(length(x)-1)/fs; % time vector 2
X=fft(x,length(x))*(2/length(x)); %fft of final signal
mag_X = abs(X); % magnitude
freq=0:1/tm(end):fs/2-(1/tm(end)); % compute frequency
plot(freq,mag_X(1:length(freq))); % fft plot
axis([0 6 0 4])
xlabel('Freq')
ylabel('Amplitude')
And if you use A1 = 1; A2 = 2; A3 = 3; A4 = 4; in your code you would get this
Più risposte (0)
Vedere anche
Categorie
Scopri di più su Get Started with Signal Processing Toolbox in Help Center e File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!