Convert logical values into numeric values
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I have a cell array 20000 rows and 20 columns with logical values:
A={0 0 0 0 1 0...
0 0 1 0 0 0
1 0 0 0 0 0
0 1 0 0 0 0 ...}
And I would like to convert this array into numeric values of 1 and 0. Can someone help me? Thank you.
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Più risposte (3)
Jonatan Tidare
il 26 Mar 2018
3 voti
double(A) works
1 Commento
Adesanya Taiwo
il 2 Mar 2024
This worked
chaman lal dewangan
il 13 Mar 2018
Modificato: chaman lal dewangan
il 13 Mar 2018
I wrote small code
for a=1:number of rows
for b=1:number of columns
if A(a,b)==true
new_matrix(a,b)=1;
else
new_matrix(a,b)=0;
end
end
end
2 Commenti
James Tursa
il 13 Mar 2018
Modificato: James Tursa
il 13 Mar 2018
This doesn't work either. Have you tried it?
??? Undefined function or method 'eq' for input arguments of type 'cell'.
Julotek
il 21 Mar 2018
for a=1:number of rows
for b=1:number of columns
if A{a,b}
new_matrix(a,b)=1;
else
new_matrix(a,b)=0;
end
end
end
That should work but it is maybe too complicated for you need.
Jonathan Patao
il 12 Mar 2018
Modificato: Jonathan Patao
il 13 Mar 2018
Try this:
B = cell2mat(A).*1;
4 Commenti
James Tursa
il 12 Mar 2018
I just did. It doesn't work:
>> A = {1 0;0 1}
A =
[1] [0]
[0] [1]
>> B = A.*1;
Undefined operator '.*' for input arguments of type 'cell'.
Star Strider
il 12 Mar 2018
@James —
Yours confirms my result:
A = {[1 0 1 1 0] == 1};
B = A.*1;
It throws the same error.
Jonathan Patao
il 13 Mar 2018
you're right, my fault. you need to convert from cell first. try:
B = cell2mat(A).*1;
Star Strider
il 13 Mar 2018
... duplicating my Answer!
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