Replace () with - using regexprep

Hi,
I have a cell array of strings look like this,
'6,844,828' '(355,537)'
'4,208,098' '(150,830)'
'3,942,604' '(185,044)'
'3,349,374' '(189,507)'
And I need to replace the () with negative signs so that I could convert them to numbers. e.g. (3) actually means -3.
So obviously I could do things like:
DataArr = strrep(DataArr,'(','-'); % replace ( with -
DataArr = strrep(DataArr,')',''); % remove )
And it works, but I really would like to know how to do that using regexprep, some thing like:
regexprep(CSmap, '\(/d{*}\)/','d{*}')
I don't know where to use \ ...
Thanks in advance!!!

 Risposta accettata

Well, just as simple as your code unless you have other requirements:
DataArr = regexprep(DataArr,'(','-'); % replace ( with -
DataArr = regexprep(DataArr,')',''); % remove )

3 Commenti

Zoe Zhang
Zoe Zhang il 6 Set 2011
Thx for your quick response. And could you explain to me why and when do people use \?
See doc regexp and follow the link for Regular Expressions. It's a quite complex topic. Mastering regular expressions takes time and practice. It makes my head spin many times. For example, if you have a string s='a1s34da3g7' and you want to pick out only digits, you can use:
>> s='a1s34da3g7';
d=regexp(s,'\d+','match')
d =
'1' '34' '3' '7'
'\d' means any numeric digit,i.e. 0-9
'+' means 1 or more repeatition
Zoe Zhang
Zoe Zhang il 6 Set 2011
Thanks again! :) I will just keep learning, learning~~

Accedi per commentare.

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