# save rows from an array

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samuel herrera il 17 Nov 2021
Risposto: Robert U il 17 Nov 2021
l=1*10^-3;
c=10*10^-9;
u=4*pi*10^-7;
e=(l*c)/u;
g=(u*G)/l;
vs=1;
f=[60 1000];
zs=50;
long=100;
x=0:0.1:100;
%condicione de la carga
zl=-1.2839j;
for ii=1:length(f)
w(ii)=2*pi*f(ii);
z0(ii)=((j*w(ii)*l)/(g+j*w(ii)*c))^(1/2);
prop(ii)=(j*w(ii)*l*(g+j*w(ii)*c))^(1/2);
A{ii}=[(z0(ii)+zs),(z0(ii)-zs);(z0(ii)-zl)*exp(-prop(ii)*long),(z0(ii)+zl)*exp(prop(ii)*long)];
ainv{ii}=inv(A{ii});
vo{ii}=ainv{ii}*[z0(ii)*vs;0];;
vp1{ii}=vo(1)
vp2{ii}=vo(2);
end
hi, does any one know how can i save vp1 and vp2 in list, is always showing me error
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### Risposte (1)

Robert U il 17 Nov 2021
Hi samuel herrera,
I guess, you would like to store the content of the cell array vo in vp1 and vp2, respectively. You have to address the correct cell:
l = 1*10^-3;
c = 10*10^-9;
u = 4*pi*10^-7;
e = (l*c)/u;
g = (u*G)/l;
vs = 1;
f = [60 1000];
zs = 50;
long = 100;
x = 0:0.1:100;
%condicione de la carga
zl = -1.2839j;
for ii=1:length(f)
w(ii) = 2*pi*f(ii);
z0(ii) = ((1j*w(ii)*l)/(g+1j*w(ii)*c))^(1/2);
prop(ii) = (1j*w(ii)*l*(g+1j*w(ii)*c))^(1/2);
A{ii} = [(z0(ii)+zs),(z0(ii)-zs);(z0(ii)-zl)*exp(-prop(ii)*long),(z0(ii)+zl)*exp(prop(ii)*long)];
ainv{ii} = inv(A{ii});
vo{ii} = ainv{ii}*[z0(ii)*vs;0];
vp1{ii} = vo{ii}(1);
vp2{ii} = vo{ii}(2);
end
Warning: Matrix is close to singular or badly scaled. Results may be inaccurate. RCOND = 8.003843e-26.
vp1
vp1 = 1×2 cell array
{[0.0256 + 0.0244i]} {[0.1030 + 0.0851i]}
vp2
vp2 = 1×2 cell array
{[9.9755e-15 + 9.8287e-15i]} {[-1.4010e-53 - 6.0898e-54i]}
Kind regards,
Robert
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