Finding a position of minimum value element in a matrix

I have matrix of 10*73 with random variable

Now i want to find out the minimum value in 13 to 20th column in each row

if i write the program like this is it work

for i=1:10
   [r1,c1]=find(a(i,1:73)==min(a(i,13:20)))

Answer 1

[KSSV]

A = rand(10,73) ;
[iwant,idx] = min(A(:,13:20),[],2)  % idx gives column position 

iwant = 10×1

0.1923 0.1928 0.1840 0.0789 0.2020 0.0124 0.5000 0.0500 0.1418 0.0890

[Matt J]

If the column position needs to be with respect to the original dimensions of A, then you also need,

idx=idx+12;