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Azzera filtri

Read file whose name has a pattern that is part of another file name pattern

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I have files with two patterns in their names: "" and "".
Currently I'm using:
filePattern = fullfile(Exp_Path,strcat('*',Sampling_Rate,'.nc'));
ncFiles = dir(filePattern);
with Sampling_Rate being a string (either 'daily' or '4xdaily'), and with Exp_Path being the directory containing the relevant files.
For the "4xdaily" pattern, this works properly, giving me a structure with all the requested files and only them.
When I try to apply this to the the "daily" pattern, I get a structure with both kinds of files (which makes sence, as the string 'daily' is included in the larger string '4xdaily').
Is there a way to obtain only the "daily" files?

Risposta accettata

Ive J
Ive J il 14 Gen 2022
Modificato: Ive J il 14 Gen 2022
Try this
files = {dir("*").name}.'
{'' }
{'' }
xdailyIdx = endsWith(files, '');
xdailyf = files(xdailyIdx)
dailyf = files(~xdailyIdx)
{'' }
  2 Commenti
Meir Zeilig Hess
Meir Zeilig Hess il 14 Gen 2022
After a small modification, it worked!
I only needed to replace the first line of your answer with:
files = {dir(filePattern).name}; % No need for transposition, but the full path was required
Then, using the index array "xdailyIdx", it was easy to manipulate not only the array of file names, "files", but also the whole structure "ncFiles".
Thank you very much!

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