Azzera filtri
Azzera filtri

Finding x for y = f(x) in simulink

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Phan Van Long
Phan Van Long il 18 Gen 2022
I have an equation which is uel = 3 + 3 * iel + 3 * log (3 * iel +1) a.k.a uel = f(iel) and I want to find iel ( uel is already known), so I have used fsolve to solve the problem in matlab and it works. Here is the code
---------------------------------------------------------------------
function iel = test(uel)
f = @(x) uel-(3 + 3 * x + 5 * log(3 * x + 1));
iel = fsolve(f,uel);
end
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But when i try to add this code into matlab function block in simulink, the model just don't run. I want my input to be uel and output to be iel. Can anyone please help me on this problem. Thank you so so much
  2 Commenti
Max Heimann
Max Heimann il 18 Gen 2022
Can you provide the error message?
Phan Van Long
Phan Van Long il 19 Gen 2022
This is the error message sir @Max Heimann

Accedi per commentare.

Risposte (2)

Paul
Paul il 19 Gen 2022
Modificato: Paul il 19 Gen 2022
According to the Symbolic Math Toolbox, the solution can be expressed as
%iel = wrightOmega(uel/3 - log(3) - 2/3) - 1/3
assuming that iel and uel are real. If they can be complex, the expression for iel is the same, but there are some other conditions that have to be satisfied.
Check
%doc wrightOmega
for more info.
Check a couple of test cases (note that I changed the 5 to a 3 in the function test() to match the equation in the question)
uel = 0.3
uel = 0.3000
iel = test(uel)
Equation solved. fsolve completed because the vector of function values is near zero as measured by the value of the function tolerance, and the problem appears regular as measured by the gradient.
iel = -0.1723
iel = wrightOmega(uel/3 - log(3) - 2/3) - 1/3
iel = -0.1723
uel = 5.4
uel = 5.4000
iel = test(uel)
Equation solved. fsolve completed because the vector of function values is near zero as measured by the value of the function tolerance, and the problem appears regular as measured by the gradient.
iel = 0.2465
iel = wrightOmega(uel/3 - log(3) - 2/3) - 1/3
iel = 0.2465
function iel = test(uel)
% f = @(x) uel-(3 + 3 * x + 5 * log(3 * x + 1)); % doesn't match equation in Question
f = @(x) uel-(3 + 3 * x + 3 * log(3 * x + 1));
iel = fsolve(f,uel);
end

Dat Trương Lê Trí
Dat Trương Lê Trí il 6 Lug 2022
Hi, I am facing the same problem, did you have any posible solution for this case?

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