Equations to Matlab code

1 visualizzazione (ultimi 30 giorni)
Maria
Maria il 18 Nov 2014
Risposto: Warren Dennis il 17 Feb 2020
hi
I want to convert the two equations below into Matlab code , I wrote the function below for that and I don't know if that is correct or not , specially the integral form ? any help ?
function [VI,Vw]= Modelfun(TL,TR)
dt=0.01; %sampling time
r=0.052;
L=0.306;
M=9;
I=5;
VI=(TL+TR)/ M * r;
VI=VI*dt/2; %first integral
Vw=(L*(TL-TR)) / 2 * r * I;
Vw=Vw*dt/2; %first integral
Vw=Vw*dt/2; %second integral
end

Risposta accettata

Torsten
Torsten il 20 Nov 2014
It is not possible simply to output (VI,Vw) given (TL,TR).
As input you need (VIold,Vwold,Vwdotold,dt,TL,TR).
The output VI,Vw and Vwdot is then calculated according to
VI=VIold+dt*(TL+TR)/(M*r)
Vw=Vwold+dt*Vwdotold
Vwdot=Vwdotold+dt*L*(TL-TR)/(2*r*I).
This would mean that your function "Modelfun" advances VI and Vw from their values at time t to time t+dt.
Best wishes
Torsten.

Più risposte (2)

Torsten
Torsten il 18 Nov 2014
If the right-hand sides of your equations does not depend on t, the solution to your differential equations is explicitely given by
VI=VI0+(TL+TR)/(M*r)*t
Vw=Vw0+Vw0dot*t+0.5*L*(TL-TR)/(2*r*I)*t^2
where
VI0=VI at time t=0
Vw0=Vw at time t=0
Vw0dot = d/dt(Vw) at time t=0.
Best wishes
Torsten.
  5 Commenti
Maria
Maria il 19 Nov 2014
thanks a lot Torsten
Actually , I am not so good with Matlab and from my little bit understanding I built this function and I don't know if that right but generally what I want to do is to write the equations above in code form inside "Embedded MATLAB Function " block with two inputs(TL,TR) and two outputs (VI,Vw) as in figure above.
thanks
Maria
Maria il 20 Nov 2014
???

Accedi per commentare.


Warren Dennis
Warren Dennis il 17 Feb 2020
k=k0e

Categorie

Scopri di più su Characters and Strings in Help Center e File Exchange

Tag

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by