help I need matlab code to to change randn instruction to rand and limit its value between 0 and 1

Risposte (2)

If you want normally distributed random numbers on the interval [0,1], this comes close:
randnlim = @(r,c) (0.1*randn(r,c) + 0.5);

4 Commenti

The ‘r’ and ‘c’ arguments are the size of the random number vector or matrix you want from the function, ‘r’ being the number of rows and ‘c’ the number of columns. If you only want one value, set ‘r’ and ‘c’ both to 1.
Yes it does!
Try this to see the distribution:
randnlim = @(r,c) (0.1*randn(r,c) + 0.5);
hist(randnlim(1,1E+6),100)
The normal distribution has infinite support — normally-distributed variables are by definition on the interval (-Inf,+Inf). This function limits the probabilities to fall within [0,1] a significant part of the time. A truly normally-distributed random variable will never be constrained within finite limits.

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randn() creates numbers outside the range 0-1. You can either remove them
r = randn(1, 100);
r(r<0) = [];
r(r>1) = [];
or clip them
r(r<0) = 0;
r(r>1) = 1;
Which do you want? Does this answer your question?

2 Commenti

no dear I need to limt the value of randn between 0 and 1 just like rand instruction
Yes dear. The code will not allow any values of r outside the [0,1] range yet it will still have the normal distribution, well as much as you can without allowing values between minus and plus infinity.
If you want to redefine randn() so that it has that name but does what my code does, then you can do that. You can override functions to make them do your own custom stuff. But you'd have to rename the original randn() first otherwise it would be recursive.
If you just want a flat distribution like rand(), then use rand().

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Richiesto:

il 20 Nov 2014

Commentato:

il 20 Nov 2014

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