help I need matlab code to to change randn instruction to rand and limit its value between 0 and 1
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help I need matlab code to to change randn instruction to rand and limit its value between 0 and 1
Risposte (2)
Star Strider
il 20 Nov 2014
If you want normally distributed random numbers on the interval [0,1], this comes close:
randnlim = @(r,c) (0.1*randn(r,c) + 0.5);
4 Commenti
maha ismail
il 20 Nov 2014
Star Strider
il 20 Nov 2014
The ‘r’ and ‘c’ arguments are the size of the random number vector or matrix you want from the function, ‘r’ being the number of rows and ‘c’ the number of columns. If you only want one value, set ‘r’ and ‘c’ both to 1.
maha ismail
il 20 Nov 2014
Star Strider
il 20 Nov 2014
Yes it does!
Try this to see the distribution:
randnlim = @(r,c) (0.1*randn(r,c) + 0.5);
hist(randnlim(1,1E+6),100)
The normal distribution has infinite support — normally-distributed variables are by definition on the interval (-Inf,+Inf). This function limits the probabilities to fall within [0,1] a significant part of the time. A truly normally-distributed random variable will never be constrained within finite limits.
Image Analyst
il 20 Nov 2014
randn() creates numbers outside the range 0-1. You can either remove them
r = randn(1, 100);
r(r<0) = [];
r(r>1) = [];
or clip them
r(r<0) = 0;
r(r>1) = 1;
Which do you want? Does this answer your question?
2 Commenti
maha ismail
il 20 Nov 2014
Image Analyst
il 20 Nov 2014
Yes dear. The code will not allow any values of r outside the [0,1] range yet it will still have the normal distribution, well as much as you can without allowing values between minus and plus infinity.
If you want to redefine randn() so that it has that name but does what my code does, then you can do that. You can override functions to make them do your own custom stuff. But you'd have to rename the original randn() first otherwise it would be recursive.
If you just want a flat distribution like rand(), then use rand().
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