Finding the determinant without det(a)
Mostra commenti meno recenti
I need to physically computate the determinant of 3x3 matrices and lower without using the det(a) function, rather loops. What's causing this error?


1 Commento
Like Max, I'm guessing that matrix a1 isn't the expected size. In the future, it's best to post the code as formatted code instead of pictures so that people can troubleshoot it.
I'm just going to throw this out there. You can reuse the code for calculating the 2x2 case.
A = rand(3);
DA1 = det(A)
DA2 = det33(A)
function D = det22(A)
D = prod(A([1 4])) - prod(A([2 3]));
end
function D = det33(A)
D = A(1,1)*det22(A(2:3,2:3)) - A(1,2)*det22(A(2:3,[1 3])) + A(1,3)*det22(A(2:3,1:2));
end
Risposta accettata
Più risposte (0)
Categorie
Scopri di più su Linear Algebra in Centro assistenza e File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!