How to implement numerical solvers

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Kevin Hanekom
Kevin Hanekom on 29 Jan 2022
Commented: Image Analyst on 19 Apr 2022
Sorry! It turned out I just needed to focus on it more myself, a little too niche! Thank you all for the help.
  7 Comments
Image Analyst
Image Analyst on 19 Apr 2022
@Kevin Hanekom, so did Star's answer below solve it???

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Answers (1)

Star Strider
Star Strider on 29 Jan 2022
The function needs to be changed so that it accepts one vector of parameters (‘b’ here) and produces a scalar value for ‘S’. Just now, it does not, and returns ‘S’ as a matrix:
b = rand(3,1)
b = 3×1
0.4067 0.4213 0.0238
[S] = YieldCriteriaOptimization(b)
S = 3×3
0.0238 -0.0002 0.0002 -0.0002 0.0000 -0.0000 0.0002 -0.0000 0.0000
function [S] = YieldCriteriaOptimization(b)
ZZ = b(1);
psi = b(2);
max = b(3);
Ry = [ cosd(ZZ) 0 sind(ZZ) ; 0 1 0; -sind(ZZ) 0 cosd(ZZ)];
Rz = [cosd(psi) -sind(psi) 0 ; sind(psi) cosd(psi) 0; 0 0 1];
R = Ry*Rz;
SigmaPrime = [[max 0 0];[0 0 0];[0 0 0];]; %unidirectional test applied in x'
S = R\SigmaPrime*R;
end
I have no idea what ‘S’ represents, so I have no idea how to transform it into a scalar. One option might be the calculate its determinant with the det function or its norm with norm, however I have no idea if either of those are even close to being appropriate.
It just somehow magickally needs to be come a scalar.
.

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