How to deal with Index exceeds the number of array elements ?

6 visualizzazioni (ultimi 30 giorni)
Hi all,
I have a signal like this (also attached).
I want to extract signal between first start and first end, second start and second end and so on. I am doing this like this:
load 'signal'
start_location = [147,222,302,379,458,538,620,698,777];
start_value = [-81.905,-87.408,-86.262,-85.463,-85.893,-84.910,-84.614,-83.543,-84.500]
end_location = [200,275,352,431,511,593,674,762];
end_value = [-85.369,-85.028,-82.240,-80.933,-80.943,-80.082,-83.108,-85.543];
plot(thigh_orient_y,'k')
hold on
plot(start_location,start_value,'ro')
plot(end_location,end_value,'g*')
h = legend('signal','start', 'end');
%Settings
a = start_location ;
b = end_location;
n = length(a);
%Extract data between red and green indices and put in cells
T_or_y_cycle = cell(n,1) ;
for i = 1:n
T_or_y_cycle{i} = thigh_orient_y(a(i):b(i)) ;
end
I am getting error
Index exceeds the number of array elements
Beacuse there is larger number of 'start' than 'end', as the signal is cut at the end. Can you please help how to deal with this?
The n cannot be lenght(b) beacuse the signal can be cut at the begging and start with 'end' like here:
  2 Commenti
Ankit
Ankit il 31 Gen 2022
Modificato: Ankit il 31 Gen 2022
How about choosing the size based on minimum value of n = min(length(a),length(b)) ?
Tomaszzz
Tomaszzz il 31 Gen 2022
Modificato: Tomaszzz il 31 Gen 2022
Thanks, this does the trick, how can I accept you answer?

Accedi per commentare.

Risposta accettata

Ankit
Ankit il 31 Gen 2022
load 'signal'
start_location = [147,222,302,379,458,538,620,698,777];
start_value = [-81.905,-87.408,-86.262,-85.463,-85.893,-84.910,-84.614,-83.543,-84.500]
end_location = [200,275,352,431,511,593,674,762];
end_value = [-85.369,-85.028,-82.240,-80.933,-80.943,-80.082,-83.108,-85.543];
plot(thigh_orient_y,'k')
hold on
plot(start_location,start_value,'ro')
plot(end_location,end_value,'g*')
h = legend('signal','start', 'end');
%Settings
a = start_location ;
b = end_location;
n = min(length(a),length(b)); % this will avoid extra start or end value.
%Extract data between red and green indices and put in cells
T_or_y_cycle = cell(n,1) ;
for i = 1:n
T_or_y_cycle{i} = thigh_orient_y(a(i):b(i)) ;
end

Più risposte (1)

KSSV
KSSV il 31 Gen 2022
Your start_location is of size 1x9. Where as end_location is only 1x8. You need to put one more index in the variable end_location.

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