Identify & Removing Linear Dependent row/s

How can I print this matrix so that it finds and prints on the screen a column of the matrix that can be deleted so that the remaining columns still span R4?

Matrix = [10,-7,1,4,6;-8,4,-6,-10,-3;-7,11,-5,-1,-8;3,-1,10,12,12]

Matrix = 4×5

10 -7 1 4 6 -8 4 -6 -10 -3 -7 11 -5 -1 -8 3 -1 10 12 12

A=[10,-7,1,4,6;-8,4,-6,-10,-3;-7,11,-5,-1,-8;3,-1,10,12,12];

%rref(A) I'm not sure how this rref would work but I know I would need an if conditional.

I can't figure out how to remove the specific column based on if it is linearly dependent/independent.

[KALYAN ACHARJYA]

What would be the expected result on the given Matrix (A) example?

[Image Analyst]

Which column do you want to delete? Just do

Matrix(:, 4) = []; % Delete column 4.

What do you mean by "still span R4"? For this 2-D Matrix, what is R4? What is your expected output?

[Ethan Maxey]

I would like the result to print the matrix without the linearly dependent column(s). R4 is the rank. It is determined by the maximum number of linearly independent columns.

The issue is I am not allowed to hard code it by just removing column 4, it has to work with any given matrix to remove the linearly dependent column(s).

Answer 1

[Voss]

How about this?

Matrix = [10,-7,1,4,6;-8,4,-6,-10,-3;-7,11,-5,-1,-8;3,-1,10,12,12]

Matrix = 4×5

10 -7 1 4 6 -8 4 -6 -10 -3 -7 11 -5 -1 -8 3 -1 10 12 12

[~,p] = rref(Matrix)

p = 1×4

1 2 3 5

removed_column_idx = setdiff(1:size(Matrix,2),p)

removed_column_idx = 4

removed_columns = Matrix(:,removed_column_idx)

removed_columns = 4×1

4 -10 -1 12

reduced_Matrix = Matrix(:,p)

reduced_Matrix = 4×4

10 -7 1 6 -8 4 -6 -3 -7 11 -5 -8 3 -1 10 12

[Ethan Maxey]

Works perfectly! Thanks!