How to run a while loop for each element in a row matrix?

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With my very basic understanding of matlab scripts, I wrote the following one to perform an iterative calculation to find x:
inv_alpha = .32
x = 0
while y < round (inv_alpha, 4)
x = x+.01
y =(round (tand (x) - deg2rad (x), 4))
end
disp (x)
disp (y)
This ran quite exactly as I expected. But now I want to run this for an array of the variable "inv_alpha", for example:
inv_alpha = linspace (0, 0.3, 10)
Therefore I expect to see 10 output values for "y". Can someone pl. help what changes I should do to the script?

Risposta accettata

VBBV
VBBV il 13 Feb 2022
Modificato: VBBV il 13 Feb 2022
inv_alpha = linspace (0, 0.3, 10)
inv_alpha = 1×10
0 0.0333 0.0667 0.1000 0.1333 0.1667 0.2000 0.2333 0.2667 0.3000
x = 0
x = 0
y = zeros(size(inv_alpha))
y = 1×10
0 0 0 0 0 0 0 0 0 0
for k = 1:length(inv_alpha)
if y(k) < round (inv_alpha(k), 4)
x = x +0.01
end
y(k) =(round (tan (x) - deg2rad (x), 4))
% k = k+1;
end
y = 1×10
0 0 0 0 0 0 0 0 0 0
x = 0.0100
y = 1×10
0 0.0098 0 0 0 0 0 0 0 0
x = 0.0200
y = 1×10
0 0.0098 0.0197 0 0 0 0 0 0 0
x = 0.0300
y = 1×10
0 0.0098 0.0197 0.0295 0 0 0 0 0 0
x = 0.0400
y = 1×10
0 0.0098 0.0197 0.0295 0.0393 0 0 0 0 0
x = 0.0500
y = 1×10
0 0.0098 0.0197 0.0295 0.0393 0.0492 0 0 0 0
x = 0.0600
y = 1×10
0 0.0098 0.0197 0.0295 0.0393 0.0492 0.0590 0 0 0
x = 0.0700
y = 1×10
0 0.0098 0.0197 0.0295 0.0393 0.0492 0.0590 0.0689 0 0
x = 0.0800
y = 1×10
0 0.0098 0.0197 0.0295 0.0393 0.0492 0.0590 0.0689 0.0788 0
x = 0.0900
y = 1×10
0 0.0098 0.0197 0.0295 0.0393 0.0492 0.0590 0.0689 0.0788 0.0887
disp (x)
0.0900
disp (y)
0 0.0098 0.0197 0.0295 0.0393 0.0492 0.0590 0.0689 0.0788 0.0887
  4 Commenti
Udhaya K
Udhaya K il 16 Feb 2022
Hi,
It worked perfectly. I changed a bit of the programme so that I get same number of x values as the number of "inv_alpha" values:
inv_alpha =[0 0.3 0.35]
x = zeros(size(inv_alpha))
y = zeros(size(inv_alpha))
for k=1:length(inv_alpha)
while y(k) < round (inv_alpha(k), 4)
x(k) = x(k)+.01
y(k) =(round (tand (x(k)) - deg2rad (x(k)), 4))
end
end
disp (x)
disp (y)
disp (k)
Thank you so much for helping!
VBBV
VBBV il 17 Feb 2022
if it worked, please accept the answer

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