sin graph plot in reverse time

if we take the value of t from 1 to 100 then plot is ok but we take the value of time in reverse then plot is not able

wrong size is showing is there any method to take value in reverse to plot for example

t=100:1

t=zeros(100.1)

y=zeros(100.1)

for i=100:1

y(i)=sin(t(i))

plot(t,y)

end

plot is not showing

Answer 1

[Arif Hoq]

i think you don't need a loop here

t=100:-1:1;
y=sin(t);
plot(t,y)

[shiv gaur]

why value on x axis forom 1 to 100 we want the value from 100 to 1

[Arif Hoq]

just put this line

set(gca,'XDir','reverse')

[Arif Hoq]

you need to x axis direction in reverse

t=100:-1:1;
y=sin(t);
plot(t,y)
set(gca, 'XDir','reverse')

[shiv gaur]

you are req to apply this in this equation

sigma = 10;beta = 8/3;rho = 28;f = @(t,a) [-sigma*a(1) + sigma*a(2); rho*a(1) - a(2) - a(1)*a(3); -beta*a(3) + a(1)*a(2)];[t,a] = ode45(f,[0 100],[1 1 1]); plot3(a(:,1),a(:,2),a(:,3))

set(gca,'XDir','reverse')