Find indices with for loop

I am designing a code to find the cheapest gear box pair that can meet a certain force requirement.

The requirement, for example in my code is WearPinionLD, is a 37x7 matrix, and Ft the force is 37x1 matrix. I intend to find the indices of the WearPinionLD of each row w.r.t the same row of Ft with for loop:

for i=1:37

index(i)=find(WearPinionLD(i,:)>=Ft(i));

end

but matlab said the LHS and RHS sized differently.

Answer 1

[VBBV]

WearPinionLD = rand(37,7);
Ft = rand(37,1);
for i=1:37
index{i} =find(WearPinionLD(i,:)>=Ft(i));
end
index.'

ans = 37×1 cell array
    {[  1 2 3 4 6 7]}
    {1×0 double     }
    {[      2 5 6 7]}
    {[          6 7]}
    {[    1 4 5 6 7]}
    {[1 2 3 4 5 6 7]}
    {1×0 double     }
    {[    2 3 4 6 7]}
    {[  2 3 4 5 6 7]}
    {[      2 3 4 7]}
    {[    1 2 5 6 7]}
    {[      1 4 6 7]}
    {[  1 2 3 4 5 6]}
    {[          3 4]}
    {[          3 6]}
    {[  1 3 4 5 6 7]}

[VBBV]

It finds indices for all columns.

[Wayne Liu]

it became 'Unable to perform assignment because the size of the left side is 1-by-1 and the size of the right side is 1-by-0.'...

[VBBV]

Try it using cell array. See the edited code above.

[VBBV]

As the indices array are irregularly sized based on find condition, use a cell array.

[Wayne Liu]

Probelm solved!!!! Thank you so much :))