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Solving a 6th order non-linear differential equation in Matlab
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2 Commenti
Risposte (2)
30 Commenti
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- Why did you choose to compute 4 residuals in the function ?
- I understand the aim of the line :
- I understand the aim of the line :
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79 Commenti
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- an experimental constant A
- a constraint imposed on the volume that gives a new equation :
with :
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- Function – For a given mesh point, the guess function must return a vector whose elements are guesses for the corresponding components of the solution. The function must be of the form y = guess(x)x is a mesh point and y is a vector whose length is the same as the number of components in the solution. For example, if yinit is a function, then at each mesh point bvpinit callsy(:,j) = guess(x(j))For multipoint boundary value problems, the guess function must be of the formy = guess(x, k)y is an initial guess for the solution at x in region k. The function must accept the input argument k, which is provided for flexibility in writing the guess function. However, the function is not required to use k.
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- Creating a system of 1st order ODE on F.
- Implementing the boundary conditions and residuals on the 3 obvious given BC.
- But how to implement the 2 other ones as a solution to an other differential equation ??
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and
for
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