Sorting the vector y wrt the vector x?

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MEET SHAH
MEET SHAH il 16 Apr 2022
Risposto: Image Analyst il 17 Apr 2022
I have two vectors x and y
x = 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 0.66
y = 0.051998 0.084698 0.117398 0.150098 0.182798 0.215498 0.248198 0.19 0.09 0.235118
I want to make the matrix [x,y] in such a way that x is in ascending, i.e., results should be
x = 0.1 0.2 0.3 0.4 0.5 0.6 0.66 0.7 0.8 0.9
y = 0.051998 0.084698 0.117398 0.150098 0.182798 0.215498 0.235118 0.248198 0.19 0.09
Any suggestions are apreciated and thankyou in advance for your help !!

Risposta accettata

Voss
Voss il 16 Apr 2022
x = [ 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 0.66 ];
y = [ 0.051998 0.084698 0.117398 0.150098 0.182798 0.215498 0.248198 0.19 0.09 0.235118 ];
[~,idx] = sort(x);
M = [x(idx); y(idx)]
M = 2×10
0.1000 0.2000 0.3000 0.4000 0.5000 0.6000 0.6600 0.7000 0.8000 0.9000 0.0520 0.0847 0.1174 0.1501 0.1828 0.2155 0.2351 0.2482 0.1900 0.0900

Più risposte (1)

Image Analyst
Image Analyst il 17 Apr 2022
Slightly different but essentially the same
x = [0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9, 0.66];
y = [0.051998, 0.084698, 0.117398, 0.150098, 0.182798, 0.2154908, 0.248198, 0.19, 0.09, 0.235118];
% Sort (and replace) x and get the order in which it was sorted.
[x, sortOrder] = sort(x, 'ascend')
x = 1×10
0.1000 0.2000 0.3000 0.4000 0.5000 0.6000 0.6600 0.7000 0.8000 0.9000
sortOrder = 1×10
1 2 3 4 5 6 10 7 8 9
% Sort y using the same order as x used, replacing original y with new, sorted y.
y = y(sortOrder)
y = 1×10
0.0520 0.0847 0.1174 0.1501 0.1828 0.2155 0.2351 0.2482 0.1900 0.0900

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