Azzera filtri
Azzera filtri

Is there any other more efficient way of writing this code?

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for tt=1:100
for t = 1:1000;
y = a*y0+e+w-a*w0;
y0 = y; w0 = w;
end
B(:,tt) = y(:,1);
end
  1 Commento
Roger Stafford
Roger Stafford il 18 Gen 2015
Modificato: Roger Stafford il 18 Gen 2015
Savvas, I suspect you have left out some of the code for these for-loops. As it stands, the code makes no sense (or at least it is extremely inefficient.) After the first inner-loop iteration the values of w and w0 are equal and unchanging and any further computation of the step "w0 = w" is a total waste of time. Also you do not reset y and w for each outer-loop (tt) iteration, which has a very suspicious look. Please give us a realistic piece of code or else give a clear verbal description of your problem.
{Note: Unless the value of 'a' is extremely close to 1, your sequence of y values will converge to an essentially constant value or else to infinity long before you reach t = 1000.)

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