sort the matrix by the order of the first row

i have a matrix.I want to sort the columns of this matrix to be 1,2,3,4,5.... (note: my real matrix is very big. I gave these matrices as an example)
for example
3 5 4 1 2
0.2 0.5 0.7 0.1 0.9
0.7 0.9 0.4 0.3 0.2
new matrix :
1 2 3 4 5
0.1 0.9 0.2 0.7 0.5
0.3 0.2 0.7 0.4 0.9
can you help me with this?
Thanks, Berfin

 Risposta accettata

A = [ ...
3 5 4 1 2
0.2 0.5 0.7 0.1 0.9
0.7 0.9 0.4 0.3 0.2];
[~,idx] = sort(A(1,:));
B = A(:,idx)
B = 3×5
1.0000 2.0000 3.0000 4.0000 5.0000 0.1000 0.9000 0.2000 0.7000 0.5000 0.3000 0.2000 0.7000 0.4000 0.9000

5 Commenti

You're welcome!
So, can we do the opposite?
For example we have a matrix A matrix
1 2 3 4 5
0.1 0.9 0.2 0.7 0.5
0.3 0.2 0.7 0.4 0.9
and there is one more matrix
3 5 4 1 2 Let's call this matrix B
Can we sort matrix A by B?
3 5 4 1 2
0.2 0.5 0.7 0.1 0.9
0.7 0.9 0.4 0.3 0.2
like this
A = [ ...
1 2 3 4 5
0.1 0.9 0.2 0.7 0.5
0.3 0.2 0.7 0.4 0.9];
B = [3 5 4 1 2];
[~,idx] = ismember(B,A(1,:));
C = A(:,idx)
C = 3×5
3.0000 5.0000 4.0000 1.0000 2.0000 0.2000 0.5000 0.7000 0.1000 0.9000 0.7000 0.9000 0.4000 0.3000 0.2000
Hi! This is so helpful--thanks so much! I had a similar question: what if you had a missing column, and you want to skip the missing column?
For example, original matrix:
A = [
5 4 1 2
0.5 0.7 0.1 0.9
0.9 0.4 0.3 0.2];
I want my new matrix to look like this:
1.0000 2.0000 0.0000 4.0000 5.0000
0.1000 0.9000 0.0000 0.7000 0.5000
0.3000 0.2000 0.0000 0.4000 0.9000
(doesn't have to be zeros as long as the column is empty)

Accedi per commentare.

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