how to compare two values that are repeated in two vectors?

Hello everyone, I'm new to matlab, I wanted to know how I can compare 2 values that are repeated between two vectors, I'll explain myself better, for example I have these two vectors.

A = [10 56 34 11 34 ];

B = [10 56 34 11 ];

Now I need to compare element by element, I mean...

vector B = [(10) 56 34 11]; element 10 is repeated in vector A? No then it is assigned the number 1.

vector B = [10 (56) 34 11 ]; element 56 is repeated in vector A? No then it is assigned the number 1.

vector B = [10 56 (34) 11 ]; element 34 is repeated in vector A? Yes! then it is assigned the number 0.

vector B = [10 56 34 (11) ]; element 34 is repeated in vector A? Yes! then it is assigned the number 1.

the result has to be an array, equal to this.

result= [10 1

56 1

34 0

11 1]

any help will be very helpful.

[Image Analyst]

What if the numbers are not in the same index in the two vectors, like

A = [10 56 34 11 34 ];
B = [11 10 56 34 5 ];

are the 10, 56, and 34 repeated in B? What's your definition of repeated?

And is this your homework (sounds like it)?

How do I get help on homework questions on MATLAB Answers? - MATLAB Answers - MATLAB Central

[giancarlo maldonado cardenas]

Maybe I expressed myself in the wrong way!

I meant for example in the vector B = [10 56 (34) 11 ]; in vector A element 34 is repeated twice? Yes! then it is assigned the number 0.

then all the other values of B are not repeated twice in A so it is assigned the label 1, the only value of B repeated twice in A is the value 34, therefore it is assigned the label 0.

Answer 1

[Voss]

A = [10 56 34 11 34 ];
B = [10 56 34 11 ];

result = [B.' sum(A==B.',2)<=1]

result = 4×2

10 1 56 1 34 0 11 1

Breaking that expression down:

A==B.' % compare each element of A to every element of B

ans = 4×5 logical array
   1   0   0   0   0
   0   1   0   0   0
   0   0   1   0   1
   0   0   0   1   0

sum(A==B.',2) % sum each row to get the number of occurrences in A of each element of B

ans = 4×1

1 1 2 1

sum(A==B.',2)<=1 % if the number of occurrences is NOT 2 or more, that's a 1 in the result, otherwise a 0

ans = 4×1 logical array
   1
   1
   0
   1

[giancarlo maldonado cardenas]

is there a way to do it with a for loop, and not altogether?

I have to compare each element of vector B and traverse vector A in search of if that element is repeated twice, then an IF condition, if label 0 is repeated, if label 1 is not repeated, but this label can also be 0 with a probability of 10%. this is my code when comparing repeated elements in a single vector.

can u help me?

[Voss]

I don't understand what you mean by "if label 0 is repeated, if label 1 is not repeated, but this label can also be 0 with a probability of 10%", but here is how you can perform the task from the original question using a for loop:

A = [10 56 34 11 34 ];
B = [10 56 34 11 ];

result = [B.' zeros(numel(B),1)];
for ii = 1:numel(B)
    result(ii,2) = nnz(A==B(ii))<=1;
end

disp(result);

    10     1
    56     1
    34     0
    11     1

Maybe that can be of use in your actual task.