Put the leading number corresponding to the number in the column

Hi all,

Continue the previous discussion here but now on a different topic.

Is there a technique to put numbers based on the row position?.For example: I'm interested in putting numbers starting with number one in column 1, numbers starting with two in column 2, and so on (see red arrow below). for details can be seen in the following illustration:

for the data are:

rowcell={'10302','20245','30108','40112','52013','85911',[],[];'10268',[],'30095','40099','52014','69944','81502',[];'10308','20258','30054','40058','57019','83511',[],[];'10307','20258','30073','40077','57018','60021','70162','83511';'10325','20232','30082','40086',[],[],[],[];'10276','20228',[],'40085','52013','81531',[],[]}

or see attachment..

much appreciated help, tks great community.

Answer 1

[Voss]

rowcell={'10302','20245','30108','40112','52013','85911',[],[];'10268',[],'30095','40099','52014','69944','81502',[];'10308','20258','30054','40058','57019','83511',[],[];'10307','20258','30073','40077','57018','60021','70162','83511';'10325','20232','30082','40086',[],[],[],[];'10276','20228',[],'40085','52013','81531',[],[]}

rowcell = 6×8 cell array
    {'10302'}    {'20245'   }    {'30108'   }    {'40112'}    {'52013'   }    {'85911'   }    {0×0 double}    {0×0 double}
    {'10268'}    {0×0 double}    {'30095'   }    {'40099'}    {'52014'   }    {'69944'   }    {'81502'   }    {0×0 double}
    {'10308'}    {'20258'   }    {'30054'   }    {'40058'}    {'57019'   }    {'83511'   }    {0×0 double}    {0×0 double}
    {'10307'}    {'20258'   }    {'30073'   }    {'40077'}    {'57018'   }    {'60021'   }    {'70162'   }    {'83511'   }
    {'10325'}    {'20232'   }    {'30082'   }    {'40086'}    {0×0 double}    {0×0 double}    {0×0 double}    {0×0 double}
    {'10276'}    {'20228'   }    {0×0 double}    {'40085'}    {'52013'   }    {'81531'   }    {0×0 double}    {0×0 double}

% replace empty cells with '0':
empty_idx = cellfun(@isempty,rowcell);
rowcell(empty_idx) = {'0'};
% get the first digit, to be used as column index:
idx = cellfun(@(x)x(1)-'0',rowcell);
% build result:
n_row = size(rowcell,1);
rowcell_arrange = cell(n_row,max(idx(:)));
for ii = 1:n_row
    % each row of the result has the non-empty cells from that row of rowcell,
    % put in column locations given by idx(ii,:) where idx(ii,:) > 0
    rowcell_arrange(ii,idx(ii,idx(ii,:) > 0)) = rowcell(ii,~empty_idx(ii,:));
end

disp(rowcell_arrange)

    {'10302'}    {'20245'   }    {'30108'   }    {'40112'}    {'52013'   }    {0×0 double}    {0×0 double}    {'85911'   }
    {'10268'}    {0×0 double}    {'30095'   }    {'40099'}    {'52014'   }    {'69944'   }    {0×0 double}    {'81502'   }
    {'10308'}    {'20258'   }    {'30054'   }    {'40058'}    {'57019'   }    {0×0 double}    {0×0 double}    {'83511'   }
    {'10307'}    {'20258'   }    {'30073'   }    {'40077'}    {'57018'   }    {'60021'   }    {'70162'   }    {'83511'   }
    {'10325'}    {'20232'   }    {'30082'   }    {'40086'}    {0×0 double}    {0×0 double}    {0×0 double}    {0×0 double}
    {'10276'}    {'20228'   }    {0×0 double}    {'40085'}    {'52013'   }    {0×0 double}    {0×0 double}    {'81531'   }

[eko supriyadi]

your code very intuitive and easy understand..tks again Voss

ES

[Voss]

You're welcome!

[eko supriyadi]

Hi Voss, i have another problem

How if the putting it's not based on the lead number?. But from inputting numbers that I have, say i have lead number like: 1, 2, 5, 55, 555, 56, 57, 58, 59, 8. In other word, i want all numbers that lead by 1 places in column 1, lead 2 in column 2, lead 5 in column 3, lead 55 in column 4, .... lead 8 ini column 10..

edited: forgot the data

rowcell={'10302','20245','50108','55112','58013','85911',[],[];
	'10268',[],'55095','56099','58014','59944','81502',[];
	'10308','20258','50054','55558','56019','83511',[],[];
	'10307','20258','50073','55077','56018','56021','58162','83511';
	'10325','20232','50082','55086',[],[],[],[];
	'10276','20228',[],'56085','59013','81531',[],[]};

this ilustration:

[Voss]

Well, that's quite a different situation than the original question. I recommend starting a new question and maybe someone can figure it out.