How can I solve this second order equation?
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if f=60 and k=0.105with plot the relationship between qf and fo?See the image
Risposte (2)
AMIT POTE
il 29 Giu 2022
Hi Shada,
Seecond order differential equations can be solved using dsolve() or ode45() function. You can go through the following documentation for better understanding
1 Commento
Sam Chak
il 29 Giu 2022
Modificato: Sam Chak
il 29 Giu 2022
It is impossible to solve the given equation because it is not a differential equation to begin with
Fo^2_(2*f*k)/Qf*(pi-2*k*f)*fo-f^2=0
There are Fo, f, k, Qf, pi, and another fo, with Fo, Qf, and fo are unknowns.
Furthermore, the underscore symbol in Fo^2_ is not intelligible from the mathematical notation perspective.
Sam Chak
il 29 Giu 2022
This is not exactly the equation given, but it should give you the idea of ''visualizing' the relationship between Fo and Qf.
f = 60;
k = 0.105;
fimplicit(@(Fo, Qf) (Fo.^2) + (2*f*k)./Qf*(pi-2*k*f).*Fo - f^2, [-0.1 0.1 -4e-3 4e-3])
grid on
xlabel('Fo')
ylabel('Qf')
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