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help n=12 for I=1:n p(I) =rand p(I) =28×p(I) p(I)=ceil(p(I)) end I need to put constraint on this code must be theres no redanandnt values ..so if n=28 p will be all the numbers from 1:28 but in random

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n=12
for I=1:n
p(I) =rand
p(I) =28×p(I)
p(I)=ceil(p(I))
end
I need to put constraint on this code must be theres no redanandnt values ..so if n=28 p will be all the numbers from 1:28 but in random
  1 Commento
Adam
Adam il 10 Feb 2015
Please keep code in the body of the question not in the title. The title should be a short description of the problem.
Also please use the {} Code block to include formatted code.

Risposte (2)

Star Strider
Star Strider il 10 Feb 2015
‘I need to put constraint on this code must be theres no redanandnt values ..so if n=28 p will be all the numbers from 1:28 but in random’
The easiest way is to use the randperm function:
n = 12;
p = randperm(n);
  5 Commenti
Star Strider
Star Strider il 10 Feb 2015
@Adam — Thank you for your Comment!
Our friendly randperm appears frequently in Answers. That’s how I learned about it, since I don’t otherwise need to use it that often.

Adam
Adam il 10 Feb 2015
Something like this would work:
nums = 1:28;
n = 28;
p = zeros(1,n);
count = numel( nums );
for i = 1:n
idx = randi(count);
p(i) = nums( idx );
nums( idx ) = [];
count = count - 1;
end
Not necessarily the most efficient way of doing it, but it will guarantee uniqueness so long as n is at most 28 (or whatever value you set as the maximum of nums.
  2 Commenti
maha ismail
maha ismail il 10 Feb 2015
my matlab is version 6.5 doesn't not have randi or randperm instructions ..I have only rand code can you rewrite the same program but with rand instruction?
Adam
Adam il 10 Feb 2015
replace:
randi( count )
with
round( rand( count ) * n )
and I think that should give you the correct answer.

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