Implement PID in ode45 code

101 visualizzazioni (ultimi 30 giorni)
Kashish Pilyal
Kashish Pilyal il 16 Ago 2022
Commentato: Kashish Pilyal il 17 Ago 2022
So, I have a ode45 function and I have an error defined in it which changes at different iterations of the solver. I was able to define the derivative part by just differentiating the error formula but I am unable to implement the integral part. The error expression is:
, where q represents position and v represents velocity. Is it possible to get the PID part in the ode function.

Risposta accettata

Sam Chak
Sam Chak il 16 Ago 2022
Modificato: Sam Chak il 17 Ago 2022
If the error is defined as
then
P part is
I part is
D part is
and you can arrange then in the state-space form. For example, a Double Integrator system
can be rewritten in state-space as:
.
The PID has 3 terms, and the state-space is in differential form. So you have no issue with the P and the D part, because they are part of the state variables. The I part is in integral form, so you have to create an additional state variable. See Example below:
[t, x] = ode45(@DIsystem, [0 20], [0; 0; 0]);
plot(t, x(:,1), 'linewidth', 1.5)
grid on, xlabel('t'), ylabel('y(t)'), % ylim([-0.2 1.2])
function dxdt = DIsystem(t, x)
dxdt = zeros(3, 1);
% construction of PID
r = 1; % reference signal
e = x(1) - r; % error signal
Kp = 1 + sqrt(2); % proportional gain
Ki = 1; % integral gain
Kd = 1 + sqrt(2); % derivative gain
u = - Kp*e - Ki*x(3) - Kd*x(2); % the PID thing
% the dynamics
A = [0 1; 0 0]; % state matrix
B = [0; 1]; % input matrix
dxdt(1:2) = A*[x(1); x(2)] + B*u; % the Double Integrator system
dxdt(3) = e; % for integral action in PID
end
  3 Commenti
Sam Chak
Sam Chak il 17 Ago 2022
I have provided an example in the Answer using a Double Integrator system:
You will get the idea of how to implement that. Hope it works out for your system.
Kashish Pilyal
Kashish Pilyal il 17 Ago 2022
Thanks I got the idea, in my case I have the error:
e_1=x(1)-( x(4)+(h_i*x(5)) );
So, If I am right I need to introduce a new state which I will be equal to this error at the end of every iteration like you did with dxdt=x(3) and in the next iteration use this state as the integral of the error.

Accedi per commentare.

Più risposte (0)

Prodotti


Release

R2021a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by