Find the position of numbers in array
27 visualizzazioni (ultimi 30 giorni)
Mostra commenti meno recenti
Hello everybody, I'm trying to find the position of some values in an array. The values i'm interested in are in a 1x182 vector and I want to find they're position in a 1x1820 vector (practically I'm just looking for a percentile). Can you guess how I can find them?
PS: i did it with a for loop using the find function but i think it is a non-efficient way, there must be an easier and fast way!
Thank a lot in advance,
Marco
0 Commenti
Risposte (3)
Walter Roberson
il 30 Set 2022
percent_present = mean(ismember(SmallVector, LargeVector)) * 100
0 Commenti
Star Strider
il 30 Set 2022
I am not certain what you are asking.
2 Commenti
Star Strider
il 30 Set 2022
Getting them is straightforward. Getting them in that exact order requires a bit of coding gymnastics —
a = [4 5 7 2 1 6 3 9 8];
b = [2 7 8];
[~,idx] = ismember(a, b);
[idx_sorted,sortidx] = sort(idx(idx>0));
idx2 = find(idx);
Result = idx2(sortidx)
.
Ergin Sezgin
il 30 Set 2022
Modificato: Ergin Sezgin
il 30 Set 2022
Hello Marco,
Following code might help with your task:
rng(2022)
inputArray = 100*rand(1,1820); % you should use your array
selectedElems = randperm(1820,182); % random indexing for subset,
yourVector = inputArray(selectedElems); % you should use your vector instead
elemPositions = zeros(size(yourVector)); % result vector for determined positions
for i=1:size(yourVector,2)
elemPositions(1,i) = find(inputArray==yourVector(1,i));
end
isequal(selectedElems, elemPositions) % Compare real and determined positions
Good luck
0 Commenti
Vedere anche
Categorie
Scopri di più su Logical in Help Center e File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!