MATLAB App Designer: How to display a scatter plot on the UIaxes with linear fit and equation of line ?

3 visualizzazioni (ultimi 30 giorni)
I am migrating my script to App Designer.
Below script (normal script) is ploting a scatter plot with displayed linear fit and equation of line (figure 1).
Normal script:
str = [107.0176, 256.7374, 257.2012, 441.7806, 420.5170, 602.7027, 591.8610, 756.6289, 896.9324];
Ec1 = [23.8829, 19.0262, 28.8904, 22.3871, 29.4871, 24.5282, 29.3028, 26.3303, 24.5477];
createfigure(str,Ec1)
Figure 1:
Above script cannot be written as such when I am migrating to App Designer. Thus I did rewrite the script (App designer script) to get the best possible same outcome but only able to generate as in figure 2. The generated figure has no equation of line displayed and the linear fit need long script for it to be plotted.
App designer script:
str = [107.0176, 256.7374, 257.2012, 441.7806, 420.5170, 602.7027, 591.8610, 756.6289, 896.9324];
Ec1 = [23.8829, 19.0262, 28.8904, 22.3871, 29.4871, 24.5282, 29.3028, 26.3303, 24.5477];
p = polyfit(str,Ec1,1);
f = polyval(p,str);
plot(app.UIAxes3,str,Ec1,'o',str,f,'-')
hold (app.UIAxes3,'on')
legend(app.UIAxes3,'show')
hold (app.UIAxes3,'off')
Figure 2:
Seek your kind help on this very issue.
disclaimer: this script is the simplified version of full script.

Risposte (1)

VBBV
VBBV il 3 Nov 2022
str = [107.0176, 256.7374, 257.2012, 441.7806, 420.5170, 602.7027, 591.8610, 756.6289, 896.9324];
Ec1 = [23.8829, 19.0262, 28.8904, 22.3871, 29.4871, 24.5282, 29.3028, 26.3303, 24.5477];
p = polyfit(str,Ec1,1);
f = polyval(p,str)
f = 1×9
24.4321 24.8096 24.8108 25.2763 25.2227 25.6821 25.6548 26.0703 26.4241
str1 = linspace(min(str),max(str),9)
str1 = 1×9
107.0176 205.7570 304.4963 403.2357 501.9750 600.7143 699.4537 798.1930 896.9324
plot(str,Ec1,'o',str1,f,'-')
  5 Commenti
VBBV
VBBV il 3 Nov 2022
Modificato: VBBV il 3 Nov 2022
To find equation, use poly2sym and to display equation in the plot use annotation or text functions using the axes handles
VBBV
VBBV il 3 Nov 2022
str = [107.0176, 256.7374, 257.2012, 441.7806, 420.5170, 602.7027, 591.8610, 756.6289, 896.9324];
Ec1 = [23.8829, 19.0262, 28.8904, 22.3871, 29.4871, 24.5282, 29.3028, 26.3303, 24.5477];
p = polyfit(str,Ec1,1);
f = polyval(p,str);
str1 = linspace(min(str),max(str),9);
y = (vpa(poly2sym([p]),3))
y = 
plot(str,Ec1,'o',str1,f,'-')
ax = gca
ax =
Axes with properties: XLim: [100 900] YLim: [18 30] XScale: 'linear' YScale: 'linear' GridLineStyle: '-' Position: [0.1300 0.1100 0.7750 0.8150] Units: 'normalized' Show all properties
text(ax,300,26,sprintf('y = %.5fx + %.2f',p(1),p(2)))

Accedi per commentare.

Categorie

Scopri di più su Creating, Deleting, and Querying Graphics Objects in Help Center e File Exchange

Prodotti


Release

R2020b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by