how to find stable and unstable spiral point?

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Yixuan Qi
Yixuan Qi il 15 Nov 2022
Risposto: Sam Chak il 14 Set 2023
Hi I am working on a differential equation given "0 == diff(x,2) + (z.*((1/3)*(diff(x))^3-diff(x)) + x)". To show wether (0,0) is a stable or unstable spiral point when z>0 and <0. also to show (0,0)is the center when z=0.

Risposte (2)

Saarthak Gupta
Saarthak Gupta il 7 Set 2023
Hi Yixuan,
I understand you are trying to find the nature of an equilibrium point (0,0) under various conditions of the parameter z, for the second-order differential equation:
The following steps can help you achieve the desired result:
  • Convert the second-order differential equation into a system of two first-order differential equations
  • Calculate the Jacobian matrix for the system
  • Find roots of the characteristic polynomial of the Jacobian at (0,0):
  • The roots hence obtained will be in terms of z i.e,
An equilibrium point is called a stable spiral point if the Jacobian matrix has two complex eigenvalues with negative real parts.
We can evaluate both cases, i.e., z > 0 and z < 0 separately. For a case, if the eigenvalues obtained in step 4 are complex with negative real parts, we can conclude that (0,0) is a stable spiral point, otherwise it is unstable.
The Symbolic Math Toolbox can be used to calculate the Jacobian, and to compute the eigenvalues.
  • The ‘jacobian’ function can be used to compute the Jacobian matrix.
  • The ‘eig’ function can be used to compute the eigenvalues of the Jacobian matrix obtained above.
Please refer to the following MATLAB documentation for more details:

Sam Chak
Sam Chak il 14 Set 2023
@Yixuan Qi, This is actually the Rayleigh Differential Equation. I assume you would like to utilize a graphical approach, as the terms "stable spiral" and "unstable spiral" suggest this. You can check out this link:
% Rayleigh Differential Equation
title('\mu < 0, Stable spiral')
title('\mu = 0, Center')
title('\mu > 0, Unstable spiral')

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