Random pulse generator
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Hello,
I'm new in Simulink and i trying to make a pulse random generator. Pulses have amplitude (+10 & -10) and width (1 ms). The signal has to be non periodic, i mean, pulses has to appear by a random series. how can i do it? I apprecitate any help. The begining of my project depend of this signal.
Thanks. Néstor.
3 Commenti
Azzi Abdelmalek
il 27 Ott 2012
Modificato: Azzi Abdelmalek
il 27 Ott 2012
What is the maximale distance between two impulses?
Néstor Monedero
il 29 Ott 2012
Azzi Abdelmalek
il 29 Ott 2012
Check the second image (modified)
set the Amplitude of the pulse generator to 2 and substract 1
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Più risposte (2)
Fangjun Jiang
il 19 Ott 2011
1 voto
Go to Simulink Sources library, there is the Random Number block and the Uniform Random Number block.
The output of the Uniform Random Number is between 0 and 1, so you'll need to use Relational Operator block to compare it with constant such as 0.1 and 0.9, and then use Switch block to output the +10 or -10 or 0 pulse value.
3 Commenti
Néstor Monedero
il 21 Ott 2011
Fangjun Jiang
il 21 Ott 2011
You can compare the random number with a constant, e.g. 0.9 and then add a zero-order holder block.
Fangjun Jiang
il 28 Nov 2011
See update.
Néstor Monedero
il 28 Nov 2011
2 Commenti
sneha j
il 3 Mag 2021
hi, there is a bug in ur code.
In the case that u(i)<-0.9, y(i) sets to -1 in the first if-block.
But wen it executes the 2nd if-block - if gets overwritten by y(i)=0 as u(i)<0.9, so it executes the else part of the block.
U need to club the the first if block with the 2nd if-else block into one if block as follows:
if(u(i)<-0.9)
y(i)=-1;
else if(u(i)>0.9)
y(i)=1;
else
y(i)=0;
end
Hope it works well.
sneha j
il 3 Mag 2021
hi Nestor, sorry i jus realised that the else if block doesnt work, so here is a workaround:
if(u<-0.5)
y=-10;
else
y=0;
end
if(u>0.5)
y=10;
end

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