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Summing the values with looping
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% i need to find the "Q" variable for every instance of "n" and divide those values by "Pr"
clear all
clc;
n=[1:1:50]
B=7.5 % angle value
%Q= (1+2*(cos(n1*B))^(5/2)+2*(cos(n2*B)^(5/2) + ... ); --> this is an
%example of how iterations should be in short; "1+2*(cos(n*B))^(5/2)"
Pr= 395
P1= Pr/Q
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Risposte (1)
Jonas
il 7 Dic 2022
you could generate all values you asked for with a single expression. if you want the sum until a specific n, use cumsum() on the resulting vector
n=1:50;
B=7.5;
Q=[1 2*cos(n*B).^(5/2)]
size(Q)
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