Azzera filtri
Azzera filtri

Calculate values inside a nested loop with different steps and store them in the same variable.

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I have a matrix (x) and want to calculate where its values are above certain thresholds and store the results in a new matrix (C). To be more specific, I need to check whether the condition sum(x>i) is met in 18 different values of i (classes). My difficulty is that I want a different step so for the first ten values step=1, while the remaining 8 while have step=5. I tried a nested loop but the result was not the expected. Any ideas how to proceed?
for i=1:10
C(i)= sum(x>i);
for j=15:5:50
C(j)= sum(x>j);
end
end

Risposta accettata

Stephen23
Stephen23 il 16 Dic 2022
Modificato: Stephen23 il 16 Dic 2022
Assuming that SUM() returns a scalar:
V = [1:10,15:5:50];
C = V; % preallocate
for k = 1:numel(V) % loop over indices, not your data values
C(k) = sum(x>V(k));
end
Note that in MATLAB it is almost always easier to iterate over indices, rather than over data values.
Or alternatively:
C = arrayfun(@(v)sum(x>v), V)

Più risposte (1)

Jiri Hajek
Jiri Hajek il 8 Dic 2022
Hi, you can use any special vector of indexes (natual numbers) like this:
j = [1:10,15:5:50];
for i=j
C(i)= sum(x>i);
end
  10 Commenti
Ancalagon8
Ancalagon8 il 16 Dic 2022
Modificato: Ancalagon8 il 17 Dic 2022
One option is to use nonzeros, but what if a value that I need is zero?
Stephen23
Stephen23 il 16 Dic 2022
Modificato: Stephen23 il 16 Dic 2022
"your answer does not help me understand why I receive 50 values instead of 18"
Basically you are doing this:
A(50) = pi
A = 1×50
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
How many elements do you expect an array to have, when you assign something to its 50th element?
"One option is to use nonzeros, but whati if a value that I need is zero?"
As I wrote earlier, just actual indices for indexing, not your data values.

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