where is the error

14 visualizzazioni (ultimi 30 giorni)
Ahmad
Ahmad il 30 Dic 2022
Commentato: Star Strider il 31 Dic 2022
I want to know where is the error please
% Symbolic
syms x(t) y(t) z(t) p k a1 a2 b2 c d sigma beta
Eqn1 = diff(x(t), t) == p*x*(1-y/k)-a1*x*y;
Eqn2 = diff(y(t), t) == c*a1*x*y-d*y-a2*y*z/(y+a2);
Eqn3 = diff(z(t), t) == sigma*z^2-beta*z^2/(y+b2);
Sols = dsolve([Eqn1, Eqn2, Eqn3])
Warning: Unable to find symbolic solution.
S= dsolve([Eqn1, Eqn2, Eqn3])
Sols
[xSol(t),ySol(t),zSol(t)] = dsolve(Eqns)
(2) Numerical Solution - see DOC:
%% Numerical solutions
ICs = [pi; pi/2; 2]; % Initial Conditions
[time, Sol]=ode45(@(t, xyz)FCN(t, xyz), [0, 10], ICs);
plot(time, Sol(:,1), 'r',time, Sol(:,2), 'g', time, Sol(:,3), 'b', 'linewidth', 2)
legend('x(t)', 'y(t)', 'z(t)'); grid on
title('Numerical Solutions')
xlabel('$t$', 'interpreter', 'latex')
ylabel('$x(t), \ y(t), \ z(t)$', 'interpreter', 'latex')
function dxyz = FCN(t, xyz)
p =.1;
k =.2;
a1 =.3;
a2 =.4;
b2 =.5;
c =.6;
d =.7;
sigma =.8;
beta =.9;
dxyz=[p*xyz(1)*(1-xyz(2)/k)-a1*xyz(1).*xyz(2);
c*a1*xyz(1).*xyz(2)-d*xyz(2)-a2*xyz(2).*xyz(3)./(xyz(2)+a2);
sigma*xyz(3).^2-(beta*xyz(3).^2)./(xyz(2)+b2)];
end
Unrecognized function or variable 'There'.
>>

Risposta accettata

Star Strider
Star Strider il 30 Dic 2022
The system is nonlinear, and not one of the few nonlinear systems that haave analytic solutions.
After commenting-out the dsolve call, it appears to provide a solution —
% Symbolic
syms x(t) y(t) z(t) p k a1 a2 b2 c d sigma beta
Eqn1 = diff(x(t), t) == p*x*(1-y/k)-a1*x*y;
Eqn2 = diff(y(t), t) == c*a1*x*y-d*y-a2*y*z/(y+a2);
Eqn3 = diff(z(t), t) == sigma*z^2-beta*z^2/(y+b2);
Sols = dsolve([Eqn1, Eqn2, Eqn3])
Warning: Unable to find symbolic solution.
Sols = [ empty sym ]
% Warning: Unable to find symbolic solution.
S= dsolve([Eqn1, Eqn2, Eqn3])
Warning: Unable to find symbolic solution.
S = [ empty sym ]
Sols
Sols = [ empty sym ]
% [xSol(t),ySol(t),zSol(t)] = dsolve(Eqns)
% (2) Numerical Solution - see DOC:
%% Numerical solutions
ICs = [pi; pi/2; 2]; % Initial Conditions
[time, Sol]=ode45(@(t, xyz)FCN(t, xyz), [0, 10], ICs);
plot(time, Sol(:,1), 'r',time, Sol(:,2), 'g', time, Sol(:,3), 'b', 'linewidth', 2)
legend('x(t)', 'y(t)', 'z(t)'); grid on
title('Numerical Solutions')
xlabel('$t$', 'interpreter', 'latex')
ylabel('$x(t), \ y(t), \ z(t)$', 'interpreter', 'latex')
function dxyz = FCN(t, xyz)
p =.1;
k =.2;
a1 =.3;
a2 =.4;
b2 =.5;
c =.6;
d =.7;
sigma =.8;
beta =.9;
dxyz=[p*xyz(1)*(1-xyz(2)/k)-a1*xyz(1).*xyz(2);
c*a1*xyz(1).*xyz(2)-d*xyz(2)-a2*xyz(2).*xyz(3)./(xyz(2)+a2);
sigma*xyz(3).^2-(beta*xyz(3).^2)./(xyz(2)+b2)];
end
.
  12 Commenti
Ahmad
Ahmad il 31 Dic 2022
Happy new year to you, i hope that both of you will have a great 2023 and being happy with full of peaceful to both of you. also we wish that peace spread over all the worlds.
Star Strider
Star Strider il 31 Dic 2022
Thank you!
And to you (and the world) as well!

Accedi per commentare.

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