Azzera filtri
Azzera filtri

Area under the Peak

4 visualizzazioni (ultimi 30 giorni)
iqra kiran
iqra kiran il 5 Feb 2023
Hello,
I am using the following code to find the width, height and area of the peak,
load('data.csv')
X = data(:,1);
Y= data(:,2);
>> plot(X,Y)
findpeaks(Y,X,'MinPeakProminence',4,'Annotate','extents')
[pks,loc,w,p] =findpeaks(Y,X);
x = 1:length(data);
x_pks = x(loc);
area = trapz(x_pks, pks)
I am getting an error to find the area,as mentioned below
Array indices must be positive integers or logical values.
please suggest me the any solution.

Risposta accettata

Sulaymon Eshkabilov
Sulaymon Eshkabilov il 5 Feb 2023
Here is the corrected code;
clearvars; clc
load('data.csv')
X = data(:,1);
Y = data(:,2);
plot(X,Y)
findpeaks(Y,X,'MinPeakProminence',4,'Annotate','extents')
[pks,Loc,width,psrom] =findpeaks(Y,X);
findpeaks(Y,X)
x = X;
% if there are more than 1 peak, then it is necessary to specify which one
x1=Loc(1)-width(1)/2;
x2=Loc(1)+width(1)/2;
area = trapz([x1,x2], [pks(1), pks(1)])
  2 Commenti
iqra kiran
iqra kiran il 6 Feb 2023
Thank you.
Sulaymon Eshkabilov
Sulaymon Eshkabilov il 6 Feb 2023
Most welcome

Accedi per commentare.

Più risposte (0)

Prodotti


Release

R2022b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by