Is there a command that can check if a string is present in a certain array and output that same string?
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Francesco Maria
il 15 Feb 2023
Commentato: Walter Roberson
il 16 Feb 2023
Hi i want to make checks to some string array with variable dimension and i tried doing what's written in the code. I know the problem is the code in the "if" but i don't know what to do... All the functions i know that find a string in an array return an array of logical 0 and 1. I can transform the array in the same dimension by putting 0 in all the seasons that aren't present and add some || in the if statement but i feel it's less practical, and i simply want to know if it's possible.
%The first column is for other purposes
L = {1, ["Spring", "Summer"]; 0, ["Winter", "Summer","Autumn"]}
i=0;
while (i<2)
i = i+1;
if (L{i,2}(:)=="Winter")
fprintf("Yes")
end
end
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Voss
il 15 Feb 2023
I'm confused about what you want the output to be.
L = {1, ["Spring", "Summer"]; 0, ["Winter", "Summer","Autumn"]};
ism = cellfun(@(x)ismember("Winter",x),L(:,2))
7 Commenti
Voss
il 16 Feb 2023
Exactly. It's the same as this:
C = {[1 2 3],[4 5 6 7],[8 9]};
f = @(x)x(1);
cellfun(f,C) % apply the function f to the contents of each cell of C
Walter Roberson
il 16 Feb 2023
ism = cellfun(@(x)ismember("Winter",x),L(:,2))
is the same as
InternalTemporaryVariable = @(x)ismember("Winter",x);
ism = cellfun(InternalTemporaryVariable, L(:,2));
clear InternalTemporaryVariable
That is, the temporary anonymous function is created before cellfun is called, and is removed after the call (because there are no more references to it.)
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