# t test ( not sure if my implementation is correct)

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Alexander Guillen il 28 Feb 2023
Suppose that I have two groups, N and R. Each group contains four columns which represent different subjects. For example (hypothetically):
N1 = [1:5]' .... N4 = [1:5]' so that N = { N1,N2,N3,N4}
R1 = [1:5]'.... R4 = [1:5]' so that R = {R1...R4}
Is it possible to enable a loop which which can perform the t-test so that I can avoid this manually:
h = ttest(N1,R1);
.
.
.
h = ttest(N1,R4);
---
h = ttest(N2,R1);
.
.
.
h = ttest(N2,R4); and so on
I understand it may be wrong my implementation of the t-test. But I would like to put into a loop what I just described. Any guidance and help will be appreciated.
##### 0 CommentiMostra -2 commenti meno recentiNascondi -2 commenti meno recenti

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### Risposta accettata

David Hill il 28 Feb 2023
h=1;
for n=1:4
for r=1:4
H(h)=ttest(N(:,n),R(:,r));
h=h+1;
end
end
H
H = 1×16
0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0
##### 2 CommentiMostra NessunoNascondi Nessuno
Alexander Guillen il 28 Feb 2023
wow thank you
Alexander Guillen il 28 Feb 2023
By any chance, do you know how I can display the columns from N and R which h = 1?

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