code is right but can not the a plot

1 visualizzazione (ultimi 30 giorni)
Hello, I do not what the mistake is? I'm getting the first plot. However, I have not been able to get the second plot. Not sure how to fix it. As alwyas any help will be greatly appreciated. Thanks
clear
clc
L = 1-0;
T = 0.06-0;
alpha = 1;
dx = 0.05;
dt = 0.001;
%Q = (alpha.*dt)/(dx.^2);
Q = 0.25;
N = L/dx +1;
M = T/dt + 1;
x = zeros(N,1);
t = zeros(M,1);
for i=1:N
x(i) = 0+(i-1).*dx;
end
for n=1:M
t(n) = 0+(n-1).*dt;
end
u = zeros(M,N);
u(:,1) = 2;
u(:,N) = 1;
u(1,2:N-1) = sin(pi.*x(2:N-1));
for n=1:M
for i=2:N-1
u(n+1,i) = Q.*u(n,i+1) + (1-2*Q).*u(n,i) + Q.*u(n,i-1)
end
end
figure(1)
plot (x,u(M,:)) %plot x vs u
title ('x vs u at t = 0.06')
xlabel ('x')
ylabel ('T')
grid on
figure(2)
plot(t, u(:,N-1)) %plot t vs u
title ('t vs u at x = 0.5')
xlabel ('time')
ylabel ('T')
  1 Commento
Cesar Cardenas
Cesar Cardenas il 5 Mar 2023
thank you. could you show me the lines where the problem is? I did not write the whole code, I just added a couple of lines to plot. Thank you.

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Risposta accettata

Star Strider
Star Strider il 5 Mar 2023
Modificato: Star Strider il 5 Mar 2023
You need to redefine ‘t’ so that it matches the row size of ‘u’:
t = linspace(0, 2.5, size(u,1));
Try this —
% clear
% clc
L = 1-0;
T = 0.06-0;
alpha = 1;
dx = 0.05;
dt = 0.001;
%Q = (alpha.*dt)/(dx.^2);
Q = 0.25;
N = L/dx +1;
M = T/dt + 1;
%x = zeros(N,1);
x = linspace(0, 2.5, 5);
% t = linspace(0, 2.5, 5);
%t = zeros(M,1);
for i=1:N
x(i) = 0+(i-1).*dx;
end
for n=1:M
t(n) = 0+(n-1).*dt;
end
u = zeros(M,N);
u(:,1) = 2;
u(:,N) = 1;
u(1,2:N-1) = sin(pi.*x(2:N-1));
for n=1:M
for i=2:N-1
u(n+1,i) = Q.*u(n,i+1) + (1-2*Q).*u(n,i) + Q.*u(n,i-1);
end
end
figure(1)
plot (x,u(M,:)) %plot x vs u
title ('x vs u at t = 0.06')
xlabel ('x')
ylabel ('T')
grid on
t = linspace(0, 2.5, size(u,1)); % Redefine 't' To Match 'u'
figure(2)
plot(t, u(:,N-1)) %plot t vs u
title ('t vs u at x = 0.5')
xlabel ('time')
ylabel ('T')
EDIT — Forgot to re-run code before posting. Now run.
.
  1 Commento
Torsten
Torsten il 5 Mar 2023
By changing t before plotting, u(:,N-1) is plotted at the wrong times.

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Più risposte (1)

Torsten
Torsten il 5 Mar 2023
Modificato: Torsten il 5 Mar 2023
If you compare size(t) and size(u,1), you will find that the number of elements of both vectors are not the same (they differ by one element). Thus the second plot command errors.
Replace
for n=1:M
for i=2:N-1
u(n+1,i) = Q.*u(n,i+1) + (1-2*Q).*u(n,i) + Q.*u(n,i-1)
end
end
by
for n=1:M-1
for i=2:N-1
u(n+1,i) = Q.*u(n,i+1) + (1-2*Q).*u(n,i) + Q.*u(n,i-1)
end
end

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