How to calculate respiratory rate from a Doppler radar signal
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Mohan kand
il 21 Mar 2023
Modificato: Mohan kand
il 19 Apr 2023
I have a respiration signal from Doppler radar (see the radar_signal.mat and ).
The sampling frequency is 2 KHz, Pulse repetition time is 0.0005 sec. I have no idea what kind of filter I need to apply to detect the respiratory signal. My goal is to use those signals to detect the Respiratory Rate, RR. Below is my MATLAB code I used to calculate the FFT and RR. I modified the code based on the work published in : https://www.sciencedirect.com/science/article/pii/S2352340921009999. Please let me know if I am correct or not.
[file,path] = uigetfile('*.txt');
Data = textread(file, '%s', 'delimiter', '\n');
% Make Data cells empty if numerical
numericalArray = cellfun(@(s) sscanf(s,'%f').' ,Data, 'un', 0);
% Get Header
header = Data(cellfun('isempty',numericalArray));
data_ADC = vertcat(numericalArray{:});
figure(5);plot(data_ADC);
Fs = 2000; % Sampling Frequency (Hz)
Fn = Fs/2; % Nyquist Frequency
Ts = 1/Fs; % Sampling Time (sec), pulse repitation time
L = numel(data_ADC);
t = linspace(0, L, L)*Ts; % Time Vector (sec)
figure(1)
plot(t, data_ADC)
grid
xlabel('Time')
ylabel('Amplitude')
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
% Signal centralization
radarSig = data_ADC - mean(data_ADC) ;
% filter
Passband_Frequency_kHz = 2;
Filtered = lowpass(radarSig,Passband_Frequency_kHz,Fs);
% FFT
[radarSpectrum_orignal, xf] = FFT(radarSig, Fs);
[radarSpectrumForResp_filtered, ~] = FFT(Filtered, Fs) ;
% Estimate respiratory rate
[radarRR] = estRR(radarSpectrumForResp_filtered, xf) ;
figure(1)
subplot(3,3,[1 2])
plot(t, radarSig)
xlabel('time (s)')
ylabel('amplitude (V)')
title('Radar raw signal')
subplot(3,3,[4 5])
plot(t, Filtered)
ylabel('amplitude (V)')
xlabel('time (s)')
subplot(3,3,3)
plot(xf, radarSpectrum_orignal)
xlabel('frequency (Hz)')
ylabel('amplitude')
title('FFT')
subplot(3,3,6)
plot(xf, radarSpectrumForResp_filtered)
xlabel('frequency (Hz)')
ylabel('amplitude')
title(['FFT', 'RR(radar): ', num2str(radarRR),' bpm'])
6 Commenti
Image Analyst
il 21 Mar 2023
A high pass filter would just make it noisier. You'd want a low pass filter. A Savitzky-Golay filter does a sliding window fit of a polynomial to your signal, which is essentially a non-linear low pass filter in the time domain. Doing a linear low pass filter in the Fourier/spectral domain by zeroing out higher temporal frequencies and then inverse transforming would give a smoother looking signal. It might be just a case of try it and see. Try both ways while adjusting parameters. What kind of filter does the literature (published papers) say to use?
Risposta accettata
Star Strider
il 21 Mar 2023
Modificato: Star Strider
il 21 Mar 2023
Perhaps something like this —
LD = load(websave('radar_signal','https://www.mathworks.com/matlabcentral/answers/uploaded_files/1331820/radar_signal.mat'));
data_ADC = LD.data_ADC;
% figure(5);plot(data_ADC);
Fs = 2000; % Sampling Frequency (Hz)
Fn = Fs/2; % Nyquist Frequency
Ts = 1/Fs; % Sampling Time (sec), pulse repitation time
L = numel(data_ADC);
t = linspace(0, L, L)*Ts; % Time Vector (sec)
figure(1)
plot(t, data_ADC)
grid
xlabel('Time')
ylabel('Amplitude')
% Signal centralization
radarSig = data_ADC - mean(data_ADC) ;
NFFT = 2^nextpow2(L)
FTs = fft(radarSig.*hann(L), NFFT)/L;
Fv = linspace(0, 1, NFFT/2+1)*Fn;
Iv = 1:numel(Fv);
figure
plot(Fv, abs(FTs(Iv))*2)
grid
xlabel('Frequency (Hz)')
ylabel('Magnitude')
xlim([0 20])
[envu,envl] = envelope(abs(FTs(Iv))*2, 10, 'peaks'); % Signal Envelope
[pks,locs] = findpeaks(envu, 'NPeaks',1); % Return Single Peak
cidx = find(diff(sign(envu - pks/2))); % Half-Magnitude Approximate Incides
[~,cidxx] = mink(abs(cidx-locs),2); % Half-Magnitude Approximate Indices
cidx = cidx(cidxx); % Choose Two Closest Indices To Central Peak Index
for k = 1:numel(cidx)
idxrng = max(1,cidx(k)-1) : min(numel(envu),cidx(k)+1);
xv(k) = interp1(envu(idxrng),Fv(idxrng),5E-3); % 'Precise' Frequency Values
end
figure
plot(Fv, abs(FTs(Iv))*2)
hold on
plot(Fv, envu, '-r')
hold off
grid
xlabel('Frequency (Hz)')
ylabel('Magnitude')
xlim([0 10])
xline(xv,'-k', "Passband Cutoff "+xv+" Hz") % Use Frequency Values To Design Bandpass Filter
% filter
Passband_Frequency_kHz = xv;
Filtered = bandpass(radarSig,Passband_Frequency_kHz,Fs, 'ImpulseResponse','iir'); % Filter Signal
[fenvu,fenvl] = envelope(Filtered, 10, 'peak'); % Envelope Of Foltered Signal
[pks,locs] = findpeaks(fenvu, 'MinPeakProminence',0.05); % Detect Upper Envelope Peaks
RRate = 1/mean(diff(t(locs)))*60; % Calculate Respiratory Rate
% FFT
% [radarSpectrum_orignal, xf] = FFT(radarSig, Fs);
% [radarSpectrumForResp_filtered, ~] = FFT(Filtered, Fs) ;
% Estimate respiratory rate
% [radarRR] = estRR(radarSpectrumForResp_filtered, xf) ;
figure(1)
subplot(3,3,[1 2])
plot(t, radarSig)
xlabel('time (s)')
ylabel('amplitude (V)')
title('Radar raw signal')
grid
subplot(3,3,[4 5])
plot(t, Filtered)
hold on
plot(t, fenvu, 'r')
plot(t(locs), pks, 'vg', 'MarkerFaceColor','g') % Plot Peaks
hold off
ylabel('amplitude (V)')
xlabel('time (s)')
grid
text(median(t), min(ylim), sprintf('Resporatory Rate = %.2f / minute',RRate), 'Horiz','center', 'Vert','bottom')
% subplot(3,3,3)
% plot(xf, radarSpectrum_orignal)
% xlabel('frequency (Hz)')
% ylabel('amplitude')
% title('FFT')
% subplot(3,3,6)
% plot(xf, radarSpectrumForResp_filtered)
% xlabel('frequency (Hz)')
% ylabel('amplitude')
% title(['FFT', 'RR(radar): ', num2str(radarRR),' bpm'])
The envelope of the filtered signal may provide additional useful information.
EDIT — (21 Mar 2023 at 20:44)
Added code to detect upper envelope peaks and calculate respiratory rate.
.
6 Commenti
Star Strider
il 22 Mar 2023
As always, my pleasure!
‘Would it be possible to ask you something regarding your code if I don't understand anything? Thanks again !’
Yes!
.
Più risposte (3)
Mohan kand
il 23 Mar 2023
Modificato: Mohan kand
il 23 Mar 2023
7 Commenti
Star Strider
il 27 Mar 2023
It would appear to me to be acceptable, however the filter appears to me to be a bit ‘aggressive’ and eliminates much of the signal detail. I made some changes (subtracting the mean of the signals before using fft on them) and co-plotted the time domain signals before and after filltering.
LD = load(websave('data_for SG','https://www.mathworks.com/matlabcentral/answers/uploaded_files/1337354/data_for%20SG.mat'));
data_ADC = LD.data_ADC;
radarSig = data_ADC;
% figure(5);plot(data_ADC);
Fs = 2000; % Sampling Frequency (Hz)
Fn = Fs/2; % Nyquist Frequency
Ts = 1/Fs; % Sampling Time (sec), pulse repitation time
L = numel(data_ADC);
t = linspace(0, L, L)*Ts; % Time Vector (sec)
% fft of raw data
NFFT = 2^nextpow2(L)
FTs = fft((radarSig-mean(radarSig)).*hann(L), NFFT)/L;
Fv = linspace(0, 1, NFFT/2+1)*Fn;
Iv = 1:numel(Fv);
figure(2)
subplot (2,2,1)
plot(Fv, abs(FTs(Iv))*2)
xlabel('Frequency (Hz)')
ylabel('Magnitude')
title('FFT signal original')
xlim([0 10]) % ADDED
% fft of filtered data
FF_sg = sgolayfilt(radarSig,3,71);
FTs_filtered = fft((FF_sg-mean(FF_sg)).*hann(L), NFFT)/L;
Fv = linspace(0, 1, NFFT/2+1)*Fn;
Iv = 1:numel(Fv);
subplot (2,2,2)
plot(Fv, abs(FTs_filtered(Iv))*2)
xlabel('Frequency (Hz)')
ylabel('Magnitude')
title('FFT signal SG_filtered')
xlim([0 10]) % ADDED
% fft of the filtered data by the fft of the raw data
tt = abs(FTs_filtered./FTs);
subplot (2,2,3)
plot(Fv, tt(Iv)*2)
xlabel('Frequency (Hz)')
ylabel('Magnitude')
title('FFT signal after divide')
xlim([0 10]) % ADDED
figure
plot(t, radarSig, 'DisplayName','Original')
hold on
plot(t, FF_sg, 'DisplayName','SG Filtered')
hold off
grid
xlim([min(t) max(t)])
xlabel('Time (s)')
ylabel('SG Filtered Signal')
I suggest experimenting with a shorter value for ‘framelen’ since it is not obvious to me how to get RR information from the filtered signal as it currently exists. Too much detail is lost, in my opinion.
.
Mohan kand
il 27 Mar 2023
13 Commenti
Star Strider
il 29 Mar 2023
‘Do you mean on-half of "fenvu" or the filterd singnal "FF_sg" or the orginal data set?’
I am referring to half of the maximum of whatever I am using as the first argument to findpeaks generally. In this instance, it is ‘fenvu’.
Mohan kand
il 18 Apr 2023
2 Commenti
Star Strider
il 18 Apr 2023
I would at least need the signals in order to attempt that. I have no idea what the video is, and I am not certain there would be a way to get data from it to allow the synchronization.
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