sub2ind with 3D matrix?
3 visualizzazioni (ultimi 30 giorni)
Mostra commenti meno recenti
given a code, for example, like this
A=rand(10,10);
indX(:,:,1)=[2,3;1,6]; indX(:,:,2)=[2,5;2,6];
indY(:,:,1)=[4,6;2,3]; indY(:,:,2)=[7,5;3,4];
for i=1:2
for j=1:2
ind=sub2ind(size(A), indX(:,:,i), indY(:,:,j));
figure,imagesc(A(ind));
end
end
I would like to obtain the same result, without using a for loop. Is there any faster way?
2 Commenti
MarKf
il 4 Apr 2023
So you want to select subsets of a matrix without a loop given 2x2 sets of indices, is that correct? Then not sure why the 3D matrix is important (they could be in cells for example), but maybe you started with it and you need to put them in indices.
That would be assuming you are using imagesc just to show the results (but then why not use disp(A(ind)) or fprintf('%d %d\n%d %d\n\n', A(ind)') or even just A(ind) without semicolon for that). Otherwise, if you need to plot, the loop is the most straightforward solution.
Since you're combining indices sets, (x1-y1,1-2,2-1,2-2 combinations) and you'd need to assign the various sub-matrices to different variables or cells or do some operations with them anyway (like imagesc above), the loop would be again still the fastest solution.
Risposte (0)
Vedere anche
Categorie
Scopri di più su Logical in Help Center e File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!