advice on how to type this formula

Hi, could I get some guidence on how to type this out, wouldn't it be: x1(t) = 1/2-1/pi*sin(4*pi/t)

[Dyuman Joshi]

Define it as an anonymous function -

x_1 = @(t) 1/2-1/pi*sin(4*pi*t)

Fore more information, refer to these -

https://in.mathworks.com/help/matlab/matlab_prog/anonymous-functions.html

https://in.mathworks.com/help/matlab/ref/function_handle.html

[Walter Roberson]

There is a small difference between this and what was asked for. What was asked for was

But this is instead

It is a small difference in what the data type of is. In the first case, it is an alias or a macro, that everywhere occurs it is to be replaced by the given expression. In the second case, is an entity of it's own, with datatype "function mapping"

[Dyuman Joshi]

You are, of course, right Walter. However, I am (still) skeptical if that is what exactly OP wants.

We can infer this, but as OP has not specified any information about that, thus I thought of providing this as an alternative.

If OP does not provide any more information, I will move my answer to a comment.

[Walter Roberson]

Your answer is probably what they were looking for ;-)

Answer 1

[Walter Roberson]

syms t
x_1(t) = 1/2-1/pi*sin(4*pi*t)

[Aster]

do i have to include syms t?

[Walter Roberson]

Well, let us try it.

Try #1:

x_1(t) = 1/2-1/pi*sin(4*pi*t)

Unrecognized function or variable 't'.

That fails.

[Walter Roberson]

Try #2:

t = 0:.1:1;      %some specific numeric t values
x_1(t) = 1/2-1/pi*sin(4*pi*t)

Array indices must be positive integers or logical values.

That fails as well.

Looks like, Yes, you do need syms t in order to write that formula.