Coefficents of piecewise polynomial in matlab

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Hi I have a simple example of piecewise polynomial from MATLAB using the function 'cscvn'
cscvn( [1 0 -1 0 1;0 1 0 -1 0] )
ans : form: 'pp'
breaks: [0 1.1892 2.3784 3.5676 4.7568]
coefs: [8×4 double]
pieces: 4
order: 4
dim: 2
My question is : How do I read the coeffiecnt matrix as shown above. I can understand from the above coefs matrix that it has 4 columns corresponding to 4 coefficents of a 4th order polynomial. But why this matrix has 8 columns? I only have 4 pieces of polynomial, then why double the number of rows in coefs matrix?
Seocnd question is : How can I use the above coefs matrix to get the equation of piecewise poilynomial

Risposte (2)

John D'Errico
John D'Errico il 22 Nov 2023
Modificato: John D'Errico il 22 Nov 2023
Do you understand the result will not be some simple polynomial like you are used to seeing?
plot([1 0 -1 0 1],[0 1 0 -1 0],'-o')
You want a curve that follows around this diamond shaped thing. So you CANNOT have a function of the form y(x). PERIOD. You cannot do so.
Instead, cscvn generates a curve as a function of a parameter, I'll call it t, where t is the arclength of the piecewise linear curve that connects those dots. So cscvn creates the pair of functions x(t), and y(t).
READ THE DOCS FOR CSCVN: cscvn
In there this scheme is explained fairly clearly.
Again, there is no simple equation of the form y(x). There cannot be, as if you look at the plot, the result cannot be a single valued function.
  4 Commenti
Walter Roberson
Walter Roberson il 23 Nov 2023
(The rows appear to alternate, one row of x, then one row of y, with the pairs repeated according to the number of pieces. So x coordinates would be (1:2:end,:) and y coordinates would be (2:2:end,:)
Bruno Luong
Bruno Luong il 24 Nov 2023
@John D'Errico "Instead, cscvn generates a curve as a function of a parameter, I'll call it t, where t is the arclength of the piecewise linear curve that connects those dots"
Actually it's the sum of the square-root of the linear arclength, this thing is called Eugene Lee centripetal parametrization according to cscvn doc

Accedi per commentare.


Bruno Luong
Bruno Luong il 24 Nov 2023
Modificato: Bruno Luong il 24 Nov 2023
Similar answer as here
points = [1 0 -1 0 1;0 1 0 -1 0];
pp = cscvn(points)
pp = struct with fields:
form: 'pp' breaks: [0 1.1892 2.3784 3.5676 4.7568] coefs: [8×4 double] pieces: 4 order: 4 dim: 2
m = pp.dim;
p = pp.pieces;
%D = diff(points,1,2);
%d = sqrt(sqrt(sum(D.^2,1)));
%t = cumsum([0 d]); % Eugene Lee's, equal to pp.breaks, see https://www.mathworks.com/help/curvefit/cscvn.html
t = pp.breaks;
ni = 200;
ti = linspace(t(1),t(end), ni);
loc = discretize(ti, t);
x = zeros(length(ti), m);
coefs = reshape(pp.coefs, m, p, []);
for k=1:p
ink = loc == k;
tik = ti(ink);
dti = tik - t(k);
for d=1:m
P = coefs(d, k, :);
x(ink,d) = polyval(P(:), dti);
end
end
close all
hold on
if m == 2
plot(points(1,:),points(2,:),'or'),
plot(x(:,1), x(:,2),'b.')
elseif m == 3
plot3(points(1,:),points(2,:),points(3,:),'or'),
plot3(x(:,1), x(:,2), x(:,3), 'b.')
else
warning('plotting not supported')
end

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