index problem while sort

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VINAY PRAJAPATI
VINAY PRAJAPATI il 1 Feb 2024
Spostato: Walter Roberson il 1 Feb 2024
I am trying to sort some positive values from one array and finding the index of that.
Omega=[1.528 -1.528 0.792 -0.792];
[NN,ind]=sort(Omega(Omega>=0));
Answer:
NN=[0.792 1.528]
but
ind=[2,1] is coming which is wrong. It should ind=[3,1].
Please help regarding this.

Risposta accettata

Dyuman Joshi
Dyuman Joshi il 1 Feb 2024
Modificato: Dyuman Joshi il 1 Feb 2024
"ind=[2,1] is coming which is wrong."
It is correct.
The input to sort() only has 2 elements, so the expectation to get [3 1] as the output is misplaced -
Omega=[1.528 -1.528 0.792 -0.792];
Omega(Omega>=0)
ans = 1×2
1.5280 0.7920
I assume you want to get the indices of these particular values from the original array, in that case, try this -
NN=sort(Omega(Omega>=0))
NN = 1×2
0.7920 1.5280
[~,idx] = ismember(NN,Omega)
idx = 1×2
3 1
Ideally, you should use ismembertol to compare floating point numbers.
However, the values here are obtained directly from the original array via indexing, so ismember() works here.
  1 Commento
VINAY PRAJAPATI
VINAY PRAJAPATI il 1 Feb 2024
Spostato: Walter Roberson il 1 Feb 2024
Thank you so much sir for solving the problem.

Accedi per commentare.

Più risposte (1)

VBBV
VBBV il 1 Feb 2024
Spostato: Dyuman Joshi il 1 Feb 2024
Here is another way to get the indices without overhead of using ismember function
Omega=[1.528 -1.528 0.792 -0.792];
[NN,ind]=sort(Omega)
NN = 1×4
-1.5280 -0.7920 0.7920 1.5280
ind = 1×4
2 4 3 1
ind(NN>0)
ans = 1×2
3 1

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