The logical indices contain a true value outside of the array bounds

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University il 14 Feb 2024
Commentato: University il 15 Feb 2024
I am trying to test the following conditions:
if intabsul == absintul && intabsur==absintur
returns the corresponding entries of the xivals and Lvals
elseif intabsul ~= absintul && intabsur~= absintur
return the corresponding entries of the xivals and Lvals
elseif intabsul == absintul && intabsur~=absintur
return the corresponding entries of the xivals and Lvals
elseif intabsul ~= absintul && intabsur==absintur
return the corresponding entries of the xivals and Lvals
else do nothing.
Here is my code:
xivals = linspace(0, 10, 10);
Lvals = linspace(2e-8, 666.7e-6, 5);
for il=1:length(Lvals);
for ixi=1:length(xivals)
%
intul(ixi, il) = trapz(yvals, uxl(:, ixi, il));
intabsul(ixi, il) = trapz(yvals, abs(uxl(:, ixi, il)));
%
intur(ixi, il) = trapz(yvals, uxr(:, ixi, il));
intabsur(ixi,il) = trapz(yvals, abs(uxr(:, ixi, il)));
%
absintul(ixi, il) = abs(trapz(yvals, uxl(:, ixi, il)));
%
absintur(ixi,il) = abs(trapz(yvals, uxr(:, ixi, il)));
end
end
And I tried:
mask1 = intabsul == absintul & intabsur == absintur;
"The logical indices contain a true value outside of the array bounds".
This error is because the entries in "mask1" are not all true "1" or false "0".
It seems mask1 have to be all '1' or '0' for it to work.
Is any where to tackle this problem using "if" statement instead using this approach?
I want corresponding xivals and Lvals if: intabsul == absintul & intabsur == absintur or
intabsul - absintul< epsilon & intabsur -absintur < epsilon, where epsilon =1e-12
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Fangjun Jiang il 14 Feb 2024
Modificato: Fangjun Jiang il 14 Feb 2024
No. The problem is about the size mis-match
a=1:3;
index=[true false true true];
a(index)
The logical indices contain a true value outside of the array bounds.
In your case, you are doing logical indexing so check the value of size(mask1) and size(xivals). They need to be same to guarantee no error like above.
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Fangjun Jiang il 15 Feb 2024
You have to figure it out yourself. There are no size info or values for those variables provided. The code can't be run.
University il 15 Feb 2024
Hi Fangjun. I have attached the data.
%
xi=xivals;
L =Lvals;
intabsul = intabsul;
intabsur =intabsur;
absintul =absintul;
absintur =absintur;
%% This is where I having an issue
test1 = intabsul == absintul & intabsur == absintur;
subset_xi_1 = xivals(test1);
subset_Lv_1 = Lvals(test1);
test2 = intabsul ~= absintul & intabsur ~= absintur;
subset_xi_2 = xivals(test2);
subset_Lv_2 = Lvals(test2);
%
test3 = intabsul ==absintul & intabsur ~= absintur;
subset_xi_3 = xivals(test3);
subset_Lv_3 = Lvals(test3);
%
test4 = intabsul ~= absintul & intabsur == absintur;
subset_xi_4 = xivals(test4);
subset_Lv_4 = Lvals(test4);

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