# The logical indices contain a true value outside of the array bounds

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University il 16 Feb 2024
Commentato: University il 16 Feb 2024
Please, how can I tackle "The logical indices contain a true value outside of the array bounds" error? I don't what exactly is the cause.
xi=xivals;
L =Lvals;
intabsul = intabsul;
intabsur =intabsur;
absintul =absintul;
absintur =absintur;
%% This is where I having an issue
test1 = intabsul == absintul & intabsur == absintur;
subset_xi_1 = xivals(test1);
The logical indices contain a true value outside of the array bounds.
subset_Lv_1 = Lvals(test1);
test2 = intabsul ~= absintul & intabsur ~= absintur;
subset_xi_2 = xivals(test2);
subset_Lv_2 = Lvals(test2);
%
test3 = intabsul ==absintul & intabsur ~= absintur;
subset_xi_3 = xivals(test3);
subset_Lv_3 = Lvals(test3);
%
test4 = intabsul ~= absintul & intabsur == absintur;
subset_xi_4 = xivals(test4);
subset_Lv_4 = Lvals(test4);
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Fangjun Jiang il 16 Feb 2024
This is the exact same question you asked previously. The cause of the problem has been clearly explained with a simple example. You have your data and you can run your code line by line, observe the value of the variable and see what is not expected and figure out a solution.
Without comments and with those confusing variable names, it's really hard to try to understand what the program tries to achieve. If you want help, you have to explain to an extent that others can understand.
University il 16 Feb 2024
Sorry, Fangjun. From the above explanation, deos mean that xivals has to 20 by 20 matrix for it work?? I just want to get the values of xivals and Lvals if this contidition: "intabsul ~= absintul & intabsur ~= absintur" is satisfied My xivals and Lvals is a vecor of length 20 each.

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### Risposta accettata

Fangjun Jiang il 16 Feb 2024
Modificato: Fangjun Jiang il 16 Feb 2024
test2 = intabsul ~= absintul & intabsur ~= absintur
the resulting "test2" is a 20x20 logical matrix. You can't use it to index a vector of 20 elements.
Do you actually want the index only if the "whole column" or "whole row" of "test2" is all true? If yes, you need to use the all() function, apply it on the column or row.
In this cases, there are three rows of "test2" are all true
test2 = intabsul ~= absintul & intabsur ~= absintur;
index=all(test2,2);
subset_xi_2 = xivals(index)
subset_Lv_2 = Lvals(index)
subset_xi_2 =
111.8421 118.4211 125.0000
subset_Lv_2 =
1.0e-05 *
0.5967 0.6317 0.6667
##### 1 CommentoMostra -1 commenti meno recentiNascondi -1 commenti meno recenti
University il 16 Feb 2024
Oh I see, thank you so much for your explanation. I understand how it works now.

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