How i can the value for x y z by using a matrix
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calculate the values of the (x,y, and z) for the following 3*3 linear algebraic equation . Where the inputs are ๐1โ3, ๐1โ3, ๐1โ3, ๐๐๐ ๐1โ3 ๐๐ ๐ฃ๐๐๐ก๐๐๐ . ๐๐๐๐๐๐๐ ๐๐๐๐ ๐๐ ๐๐๐๐ก๐๐๐๐ โถ ๐1๐ฅ + ๐1๐ฆ + ๐1๐ง = ๐1 ๐2๐ฅ + ๐2๐ฆ + ๐2๐ง = ๐2 ๐3๐ฅ + ๐3๐ฆ + ๐3๐ง = ๐3 Try the code by entering different values of vectors.
1 Commento
Dyuman Joshi
il 29 Mar 2024
How would you solve this on pen and paper utilizing concepts of Linear Algebra?
Risposte (1)
Gayatri
il 2 Apr 2024
Hi Abdul,
To solve the given system of linear equations โถ ๐1๐ฅ + ๐1๐ฆ + ๐1๐ง = ๐1, ๐2๐ฅ + ๐2๐ฆ + ๐2๐ง = ๐2 and ๐3๐ฅ + ๐3๐ฆ + ๐3๐ง = ๐3โ, use the โlinsolveโ function.
function [x, y, z] = solveLinearEquations(a, b, c, q)
A = [a(1), b(1), c(1); a(2), b(2), c(2); a(3), b(3), c(3)];
Q = [q(1); q(2); q(3)];
solution = linsolve(A, Q);
x = solution(1);
y = solution(2);
z = solution(3);
end
Enter the different values for the coefficient vectors a, b, c and the constant vector q, then call the โsolveLinearEquationsโ function.
Please refer the below documentation for โlinsolveโ function:
I hope it helps!
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