Azzera filtri
Azzera filtri

Plot of histogram and probability distribution function.

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I have three columns of data. I am plotting histogram and normal distribution probability density function (pdf) for each column. For one column, I get its histogram and pdf shown by two different colours in plot and I get two indicators in legend. Similarly, I get histogram and pdf for remaining two columns of data. In total, I get 6 indicators with 6 different colors in legend. I want to get histogram and pdf of one column of data with same colour and show indicator only for histogram. Similarly, I want to get histogram and pdf for remaining two columns so that I get three colours for three columns of data.
Thankyou
x = (1:1:100)';
y = (101:1:200)';
z = (201:1:300)';
p1 = fitdist(x,'Normal');
p2 = fitdist(y,'Normal');
p3 = fitdist(z,'Normal');
plot(p1)
hold on
plot(p2)
plot(p3)
legend('5%','5%','10%','10%','15%','15%');
hold off

Risposta accettata

Adam Danz
Adam Danz il 12 Apr 2024
Modificato: Adam Danz il 12 Apr 2024
To equate the colors between the histogram and line pairs, access the object handles from the plot output and then set the SeriesIndex property to the same value. See a note at the bottom of this solution to control the color.
To show only the histogram objects in the legend, specify the histogram handles in the legend command. I also defined the legend strings using the DisplayName properties. Note that the fitdist plot will return a 1x2 vector of handles where the first handle is the line object and the second is the histogram.
x = (1:1:100)';
y = (101:1:200)';
z = (201:1:300)';
p1 = fitdist(x,'Normal');
p2 = fitdist(y,'Normal');
p3 = fitdist(z,'Normal');
h1 = plot(p1);
set(h1,'SeriesIndex',1)
h1(2).DisplayName = '5%';
hold on
h2 = plot(p2);
set(h2,'SeriesIndex',2)
h2(2).DisplayName = '10%';
h3 = plot(p3);
set(h3,'SeriesIndex',3)
h3(2).DisplayName = '15%';
legend([h1(2),h2(2),h3(2)]);
hold off
To control the color of the line-histogram pairs set the axes colororder.
ax = gca();
ax.ColorOrder = [1 0 0; 0 0 1; 1 0 1];

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