How can I make the layout in the attached image with tiledlayout

I am able to get plot 1 and plot 2 in but not 3, 4 and 5. I can also get 3, 4 and 5 in without plot 1 and 2 but that is not what I want, per the attached image.

Answer 1

[Star Strider]

It took a few experiments to get this to work.

Try this —

x = 0:0.1:31;
y = sin((1:5).'*x*2*pi/32);

figure
tiledlayout(4,4)
nexttile([1 2])
plot(x,y(1,:))
grid
title('Plot 1')
nexttile([2 2])
plot(x,y(3,:))
grid
title('Plot 3')
nexttile([1 2])
plot(x, y(2,:))
grid
title('Plot 2')
nexttile([2 2])
plot(x, y(4,:))
grid
title('Plot 4')
nexttile([2 2])
plot(x, y(5,:))
grid
title('Plot 5')

EDIT — Corrected typographical errors.

.

Answer 2

[Matt J]

If you download nestedLayouts,

https://www.mathworks.com/matlabcentral/fileexchange/161736-grids-of-tiled-chart-layouts

then you can do,

x = 0:0.1:31;
y = sin((1:5).'*x*2*pi/32);

[ax,t]=nestedLayouts([2,2],[2,1]);
delete(ax([4,6,8]));
ax=ax([1,2,3,5,7]);

for k=1:numel(ax)

 plot(ax(k), x,y(k,:)); 
 
 title(ax(k), "Plot "+k);
 
 if k>2, ax(k).Layout.TileSpan=[2,1]; end
 
end
for i=1:numel(t), ylabel(t(i),"YLabel "+i); end

Answer 3

[Image Analyst]

If you understand how subplots work, it's easy. The bottom and right plots just use a 2,2 layout while the upper left two use a 4,2 layout:

subplot(4, 2, 1);
title('Plot 1');
subplot(4, 2, 3);
title('Plot 2');
subplot(2, 2, 2);
title('Plot 3');
subplot(2, 2, 3);
title('Plot 4');
subplot(2, 2, 4);
title('Plot 5');

Many people don't realize it but whatever layout you use for your first subplot(s) does not need to be used for ALL subplots on the figure, so you can switch from 4 rows, 2 columns to 2 rows and 2 columns like I did above.