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Complex Integration in MATLAB with symbolic integration limits

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I'm having trouble with integrating this using MATLAB. When i try and run it as shown below, the answer that comes out i'm pretty sure is wrong. This is the first time i'm using matlab to help with integration so apologies in advance if i'm doing something very silly. Can anyone give me some pointers as to what i'm doing wrong?
syms y b n_1 n_2 R
b_y = (b-((b-(b/4))/(n_1+n_2))*y);
x = (y^2*b_y)/(1+(y/R));
I = int(x,-n_1,n_2)
I = 
  5 Commenti
Elliott Kitson
Elliott Kitson il 25 Giu 2024 alle 14:34
What do you mean by "is -R in the interval of integration"? - Really sorry, i'm not familiar with that term. But eta1 and eta2 are both positive values and all parameters involved are real numbers. Appreciate your time helping! :)
Torsten
Torsten il 25 Giu 2024 alle 17:40
Modificato: Torsten il 25 Giu 2024 alle 17:41
What do you mean by "is -R in the interval of integration"?
If -R is in the interval [-eta1 eta2], the denominator of your integrand becomes 0 and your integrand +/- Infinity or NaN.
Similar to
syms x
f = 1/(1-x);
int(f,x,0.5,1.5)
ans = 
NaN

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Torsten
Torsten il 25 Giu 2024 alle 17:46
Modificato: Torsten il 25 Giu 2024 alle 18:06
Does this help ?
Note that no distiction is made about the R-value. But you should keep in mind that the answer is incorrect if -R is in the interval [-eta1 eta2].
syms y b n_1 n_2 R
b_y = (b-((b-(b/4))/(n_1+n_2))*y);
x = (y^2*b_y)/(1+(y/R));
I = int(x,y);
simplify(subs(I,y,n_2)-subs(I,y,-n_1))
ans = 
  3 Commenti
Torsten
Torsten il 25 Giu 2024 alle 23:05
Does this then mean that the solution you provided below would be valid?
Yes.
Elliott Kitson
Elliott Kitson il 25 Giu 2024 alle 23:21
Thanks for the help! Massively appreciate it :)

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