Alternative to ginput for finding curve intersections with unevenly spaced data in MATLAB
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Is there a better way to determine the intersection of two curves in MATLAB, other than using ginput, especially when the data points are unevenly spaced and do not include the exact intersection point? How can I handle cases where one of my datasets forms two angled lines joined together, rather than a smooth curve?

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Matt J
il 8 Feb 2025
Modificato: Matt J
il 8 Feb 2025
Use fminbnd or fzero,
x=sort(rand(1,12)*5);
y1=[0,1,-1*x(3:end)+3+2*x(3)];
y2=2*x-3;
f=@(z) interp1(x,y1,z)-interp1(x,y2,z) ;
xmin=fzero(f,[min(x),max(x)]); ymin=interp1(x,y1,xmin); %intersection
h=plot(x,y1,'--gx', x,y2,'--b+',xmin,ymin,'ro');
h(3).MarkerFaceColor=h(3).Color; h(3).MarkerSize=8;
Più risposte (2)
Alan Stevens
il 8 Feb 2025
Create a function using interp1 for use with fzero. For example:
yfn = @(X,Y,x) interp1(X,Y,x);
X = [1,2,3,7,8,9];
Y1 = X;
Y2 = 15-X.^1.5;
x0 = 6;
xp = fzero(@(x0)fn(x0,X,Y1,Y2,yfn),x0);
disp(xp)
yp = yfn(X,Y1,xp);
plot(X,Y1,'-o',X,Y2,'-+',xp,yp,'ks'),grid
xlabel('x'), ylabel('y')
function Z = fn(x,X,Y1,Y2,yfn)
Z = yfn(X,Y1,x)-yfn(X,Y2,x);
end
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Star Strider
il 8 Feb 2025
Modificato: Star Strider
il 9 Feb 2025
Another approach —
x = [linspace(0, 2.4) linspace(5.2, 7, 8)].'*1E-3;
y1 = [x(x<=2.4E-3)*580/2.4E-3; 500*ones(size(x(x>2.5E-3)))];
y2 = x*580/2.4E-3 - 450;
idx = find(diff(sign(y2 - y1)))
idxrng = max(1,idx) : min(numel(x),idx+1)
y2(idxrng)-y1(idxrng)
xi = interp1((y1(idxrng)-y2(idxrng)), x(idxrng), 0)
yi = interp1(x, y1, xi)
figure
plot(x, y1, '.-', DisplayName="y_1")
hold on
plot(x, y2, '.-', DisplayName="y_2")
plot(xi, yi, 'sr', DisplayName="Intersection")
hold off
grid
legend(Location='best')
This approach finds the approximate index of the two lines and then interpolates to find the intersection points of the lines.
EDIT — (9 Feb 2025 at 1:43)
Corrected code.
.
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